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3 years ago

The second one and the third one

Mathematics

1 answer:

Fynjy0 [20]3 years ago

5 0

The answer to the thrd one is 52

how you do it is by multiplying the 6.5 by 8

and that gives your the answer of 52

idk about the other one cuz my answer came out to be .010 soooo ya idk if u should trust me on that one

anyways hope this helps!

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Which expressions are equivalent to 4^-2 times 7^-2

Harlamova29_29 [7]

Step-by-step explanation:

$= {4}^{ - 2} \times {7}^{ - 2}$

$= {(4 \times 7)}^{ - 2}$

$= {28}^{ - 2}$

$= \frac{1}{ {28}^{2} }$

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3 years ago

−4 + 9 − r − 5 in an equation

SVETLANKA909090 [29]

Answer:

Deez N--utz

Step-by-step explanation:

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3 years ago

Read 2 more answers

A person who is 68in tall casts a shadow that is 54in long. At the same moment, a tree casts a shadow that is 18ft long. What is

34kurt

Answer:

22.67 ft is the height of tree.

Step-by-step explanation:

Given:

Height of a person is 68 in and casts a shadow that is 54 in long.

At the same point, a tree casts a shadow that is 18 ft long.

Now, to find the height of tree.

Let the height of tree be $x.$

If height of a person is 68 in he casts a shadow of 54 in.

So, 68 in is equivalent to 54 in.

Thus, $x$ is equivalent to 18 ft.

Now, to get the height of tree by using cross multiplication method:

$\frac{68}{54} =\frac{x}{18}$

By cross multiplying we get:

$1224=54x$

Dividing both sides by 54 we get:

$22.67=x$

$x=22.67\ ft.$

Therefore, the height of the tree is 22.67 ft.

6 0

3 years ago

Which expression is equivalent to 6x3 + 3y2 – 5x3 + 2y2?

iVinArrow [24]

The answer is C because 6X^3 minus 5X^3 is just X^3 and 3Y^2 plus 2Y^2 is 5Y^2.

4 0

3 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

3 years ago