Answer:
The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.
The answer is 42 mpg, all you need to do is divide 126/3 or 210/5 and they both equal 42.
The number of hours that students have to work on homework will be 1/3 hours.
<h3>What is subtraction?</h3>
It simply implies subtracting something from an entity, group, location, etc. Subtracting from a collection or a list of ways is known as subtraction.
Mr. K's maths class is 1 and 1/4 hours long.
After working problems on the board for 55 minutes or 11 / 12 hour.
He gave the students the rest of the class period to work on homework.
Then the number of hours that students have to work on homework will be
⇒ 1 + 1/4 - 11/12
⇒ 5 / 4 - 11/ 12
⇒ (15 - 11) / 12
⇒ 4/12
⇒ 1/3 hours
More about the subtraction link is given below.
brainly.com/question/4319655
#SPJ1
Answer:
a = -0.3575
Step-by-step explanation:
The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.
The points A and B are located where

This gives


Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

Thus the coordinates of B are:

Now this point B lies on the parabola, and therefore it must satisfy the equation 
Thus

Therefore

