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borishaifa [10]
3 years ago
11

What is the vertex of the parabola y=2x2+20x-15? (5, 135) (-5, -165) (-5, -65)

Mathematics
1 answer:
maria [59]3 years ago
5 0

Answer:

-296=2×2+20×-15that is the answer

Step-by-step explanation:

you need to calculate the equation step by step to get to the answer

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Please help find them <br>1 AB<br><br>2 BC​
spin [16.1K]

Answer:

AB ≈ 15.7 cm, BC ≈ 18.7 cm

Step-by-step explanation:

(1)

Using the Cosine rule in Δ ABD

AB² = 12.4² + 16.5² - (2 × 12.4 × 16.5 × cos64° )

       = 153.76 + 272.25 - (409.2 cos64° )

       = 426.01 - 179.38

       = 246.63 ( take the square root of both sides )

AB = \sqrt{246.63} ≈ 15.7 cm ( to 1 dec. place )

(2)

Calculate ∠ BCD in Δ BCD

∠ BCD = 180° - (53 +  95)° ← angle sum in triangle

∠ BCD = 180° - 148° = 32°

Using the Sine rule in Δ BCD

\frac{BC}{sin53} = \frac{BD}{sin32} = \frac{12.4}{sin32} ( cross- multiply )

BC × sin32° = 12.4 × sin53° ( divide both sides by sin32° )

BC = \frac{12.4sin53}{sin32} ≈ 18.7 cm ( to 1 dec. place )

         

6 0
2 years ago
What was the equation of the graph below before it was shifted to the right 1 unit? (equation was g(x)=(x-1.5)^3-(x-1.5))
harina [27]
If graph of the function y=f(x) was shifted to the  right 1 unit, then you got new function y=f(x-1).
Reversly, if you have the function g(x)=(x-1.5)^3-(x-1.5) that is obtained by shifting to the right 1 unit, then the initial function was

g(x+1)=(x+1-1.5)^3-(x+1-1.5), \\ g(x+1)=(x-0.5)^3-(x-0.5).
Answer: Correct choice is D.
3 0
3 years ago
Read 2 more answers
In the above figure, the radius of curvature is 10 ft and the height of the segment is 2 ft. What's the length of the chord?
Kay [80]
The answer is 12. I am 1,000,000% positive that it is the correct answer

4 0
3 years ago
Help me with problem 2 please
e-lub [12.9K]

Answer:

Second choice, 11/30

Step-by-step explanation:

38 + 22 = 60

He flipped tails 22 times out of 60 tries, so it's 22/60

Simplify with 2 and it's 11/30

8 0
2 years ago
Given: ABCD is a parallelogram and AC bisects BD.<br> Prove: AB is congruent to BC.
earnstyle [38]

Let's see

In ∆ABE and ∆CBE

  • BE=BE(Common side)
  • AE=EC[Diagonals of a parallelogram bisect each other]
  • <AEB=<BEC[90°]

So by

SAS congruence the triangles are congruent

AB=BC

  • Proved

Fact:-

It's already given AC is perpendicular to BD

  • It means diagonals are perpendicular to each other

According to general property of rhombus this parallelogram is also a rhombus.

So sides are equal hence AB =BC

3 0
1 year ago
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