Answer:
9
Step-by-step explanation:
18:2
?:1
?=9
Answer:
The estimate of In(1.4) is the first five non-zero terms.
Step-by-step explanation:
From the given information:
We are to find the estimate of In(1 . 4) within 0.001 by applying the function of the Maclaurin series for f(x) = In (1 + x)
So, by the application of Maclurin Series which can be expressed as:

Let examine f(x) = In(1+x), then find its derivatives;
f(x) = In(1+x)

f'(0) 
f ' ' (x) 
f ' ' (x) 
f ' ' '(x) 
f ' ' '(x) 
f ' ' ' '(x) 
f ' ' ' '(x) 
f ' ' ' ' ' (x) 
f ' ' ' ' ' (x) 
Now, the next process is to substitute the above values back into equation (1)



To estimate the value of In(1.4), let's replace x with 0.4


Therefore, from the above calculations, we will realize that the value of
as well as
which are less than 0.001
Hence, the estimate of In(1.4) to the term is
is said to be enough to justify our claim.
∴
The estimate of In(1.4) is the first five non-zero terms.
Answer:
If this is asking for the set:
Z = {-3, -2, -1, 0, 1, 2, 3}
Step-by-step explanation:
Z is the set of all integers and it appears that you are being asked for the values in the set Z that are within the range: -3 ≤x ≤ 3
Answer:
The answer is D.
Step-by-step explanation:
When x=0, then y=300, so it has to be more than that.
When x=25, y=300, so it has to be less than that.
Answer:
Step-by-step explanation:
18=2×3×3
48=2×2×2×2×3
G.C.F.=2×3=6
18+48=66
6×11=66