Answer:
// here is code in java.
import java.util.*;
class Solution
{
// main method of class
public static void main (String[] args) throws java.lang.Exception
{
try{
// declare variable
double caffeine;
// scanner object to read input from user
Scanner scr=new Scanner(System.in);
System.out.print("Enter the initial amount of caffeine:");
// read the initial amount of caffeine
caffeine=scr.nextDouble();
// calculate amount of caffeine after 6,12,18 hours
for(int i=1;i<=3;i++)
{
System.out.println("After "+ i*6+" hours:"+(caffeine/2)+" mg");
// update the caffeine after every 6 hours
caffeine=caffeine/2;
}
}catch(Exception ex){
return;}
}
}
Explanation:
Create a variable "caffeine" to store the initial amount of caffeine given by user. Run a loop for three time, it will calculate the amount of caffeine left after every 6 hours.First it will give the amount of caffeine left after 6 hours, then caffeine left after 12 hours and in last caffeine after 18 hours.
Output:
Enter the initial amount of caffeine:100
After6 hours:50.0 mg
After12 hours:25.0 mg
After18 hours:12.5 mg
Answer:
In Python:
def fib(nterms):
n1, n2 = 1, 1
count = 0
while count < nterms:
term = n1
nth = n1 + n2
n1 = n2
n2 = nth
count += 1
return term
Explanation:
This line defines the function
def fib(nterms):
This line initializes the first and second terms to 1
n1, n2 = 1, 1
This line initializes the Fibonacci count to 0
count = 0
The following while loops gets the number at the position of nterms
<em> while count < nterms:
</em>
<em> term = n1
</em>
<em> nth = n1 + n2
</em>
<em> n1 = n2
</em>
<em> n2 = nth
</em>
<em> count += 1
</em>
This returns the Fibonnaci term
return term
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Answer:
I believe the answer is exclusive but im not 100% sure
guess its d drivers , since u said wen it gets outdated