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Shkiper50 [21]
3 years ago
6

A(n) _____ is a type of server that stores computer software, which users can access from their workstations.

Computers and Technology
1 answer:
Olenka [21]3 years ago
6 0

Answer:

Application server

Explanation:

In networking, services are used in networks to provides centralized services which is needed by all the devices in the network. It reduces the time and effort, needed by a network administrator to configure these services on different workstations.

There are various types of servers, they TFTP, DHCP, DNS, FTP, Web servers etc. There are also categories of server ranging from Web servers to file servers and then application server.

Application servers stores computer softwares (even computer operating system ), for users to access from their workstations.

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Create a base class named rectangle that contains lenght and width data members.
kumpel [21]

Answer:

class Rectangle:  

   

   def __init__(self, length, width):

       self.length = length

       self.width = width

       

   

   def area(self):

       area = self.length*self.width

       return area

   

   

class Box (Rectangle):

   

   def __init__(self, length, width, height):

       super().__init__(length, width)

       self.height = height

       

   def volume(self):

       volume = self.length * self.width * self.height

       return volume

   

   def area(self):

       area = 2*(self.length*self.width) + 2*(self.length*self.height) + 2*(self.width*self.height)

       return area

rec_1 = Rectangle(2,4)

box_1 = Box(2,2,6)

print(box_1.length)

print(box_1.area())

   

print(rec_1.length)

print(rec_1.area())

Explanation:

The programming language used is python.

class Rectangle

The class Rectangle is created with attributes length and width.

The class attributes are initialized using the __init__ constructor.

In the rectangle class, a method/function is declared to return the area of the rectangle.

class Box

This class is a child of rectangle and it inherits all its attributes and methods,

It has an additional attribute of depth and its constructor is used to initialize it.

The class contains a volume function, that returns the volume and an override function 'area()' that displaces the area from the parent class.

Finally, some instances of both classes are created.

4 0
3 years ago
Pls answer 10 points ​
AlekseyPX

Answer:

1. C

5.b

Explanation:

1. Is c because it is in the short cut key

5. Is B because it is the last choice

3 0
2 years ago
Read 2 more answers
The code size of 2-address instruction is________________.? 5 bytes? 7 bytes? 3 bytes? 2 bytes
Finger [1]

Answer:

7 bytes

Explanation:

<u>2 Address Instruction</u>

The 2 address instruction consist 3 components in the format.

One is opcode,other two are addresses of destination and source.

<u>Example-</u>

load b,c | Opcode   destination address,source address

add a,d  | Opcode   destination address,source address

sub c,f    | Opcode   destination address,source address

Opcode consists of 1 bytes whereas destination address and source address consist of 3 bytes each.

(1+3+3) bytes=7 bytes

5 0
3 years ago
If Count = 1 and X = 3, what will be displayed when code corresponding to the following pseudocode is run? Do Set Y = Count + X
kirill115 [55]

Answer:

4 5 6

Explanation:

Since there is a do-while loop, you need to check the values for each iteration until the condition (Count <= X) is not satisfied.

First iteration ->  Count = 1 and X = 3, Y = 1 + 3, Write Y -> 4

Second iteration ->  Count = 2 and X = 3, Y = 2 + 3, Write Y -> 5

Third iteration ->  Count = 3 and X = 3, Y = 3 + 3, Write Y -> 6

After the third iteration count is equal to 4 and X is equal to 3. That is why loop ends.

3 0
3 years ago
Suppose I define some structure type ( studentInfo), then I declare an instance of it and I decide to also create a pointer to t
Nookie1986 [14]

Answer:

a. (p*Main).age = 20;

Explanation:

Pointers use ->

where as normal variable use . to access its members

pMain is the pointer.

*pMain is the value inside pMain.

pMain->age = 20;

This statement equals to

(*pMain).age = 20;

Answer is option a.

8 0
3 years ago
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