You want to write this equation in the form (x+...)(x+...) (maybe with a minus sign). To do this, find numbers that, when multiplied, give 16, and when added give -10.
What whole numbers give 16?
1*16 and -1*-16
2*8 and -2*-8
4*4 and -4*-4
Which of these solutions, when changed into a sum, give -10?
Try them one by one and find it is:
-2-8 = -10.
So (x-2)(x-8) is the factorization!
This is really a bit of trial and error, but since most of the time the assignments deals with whole numbers, there aren't that many possibilities.
Answer:
X= -3 and X= -5
Step-by-step explanation:
(x+3)(x+5)= 0
-Set factors equal to 0
X+3 = 0 X+5 = 0
(Move the 3 on the other side of the equal sign just by subtracting it from zero. After that, do the same for 5)
And you get: X= -3 and X= -5
E: when looking at the line it starts from 0-1 and we’re looking for 0.97 which is 0.03 away from 1 meaning it’s going to be the closest to one
Answer:
O
Step-by-step explanation:
