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Anastasy [175]
4 years ago
11

What plane contains E,F,and H

Mathematics
2 answers:
Sati [7]4 years ago
7 0
...no one can answer u bc theres no pic soooo yea
kvasek [131]4 years ago
5 0

B. The plane on the bottom of the figure

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One pound of chicken cost $3. Jims buys 8 2/3 pounds. How much does he pay
seropon [69]
He will pay 26.1$ for 8 2/3 pounds of chicken.

Hope this helps!!

3 0
3 years ago
Read 2 more answers
6+t is less than or equal to 13
Vlad [161]
If 6+t ≤13, then t ≤ 7

6 + t ≤ 13
-6        -6
t ≤ 7

When subtracting 6 from positive 6 they cancel out leaving t. Then 13 - 6 = 7.
4 0
4 years ago
Read 2 more answers
What is the square root of negitive 64
Alina [70]

Answer:

8i

Step-by-step explanation:

-(root of 64)


but if you mean


root of -64 then it's 8i if you have learned complex numbers

can i get brainliest ;)

8 0
3 years ago
Read 2 more answers
im rlly confused (its yes and no answers)Decide if each pair of expressions is equivalent.6(-4t + 5) and -2(15 - 12t)1/5(20t - 1
kirill [66]

Given data:

The expression of the first option is,

\begin{gathered} \text{6(-4t+5})and\text{-2(15}-12t) \\ =-6(5-4t) \end{gathered}

Thus, the above expression are not equivalent.

The expression in the second option is,

\begin{gathered} \frac{1}{5}(20t-15)\text{ and }4t-3 \\ 4t-3\text{ and 4t-3} \end{gathered}

Thus, yes they are equivalent.

The expression in the third option is,

\begin{gathered} 1.5\text{ }-2\text{t and 0}.25(8-6t) \\ 1.5\text{ }-2\text{t and 2-1.5t} \end{gathered}

Thus, the above expression are not equivalent.

The expression in fourth option is,

\begin{gathered} -3(t-7+5t+8)\text{ and }-18t-3 \\ -3(6t+1)\text{ and -18t-3} \\ -18t-3\text{ and -18t-3} \end{gathered}

Thus, yes the above expression is equivalent.

3 0
2 years ago
Is (3,13) a solution of y = 2x - y
PtichkaEL [24]

Answer:

NO

Step-by-step explanation:

(x, y) so if you plug in your points... 13 = 2(3) - 13

To solve:

Multiply:    13 = 2(3) - 13

Subtract:   13 = 6 - 13

Answer:     13 does not equal -7

5 0
3 years ago
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