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miss Akunina [59]
3 years ago
11

What is the 100th term of the sequence if the first term is 5 and the common difference is 2?

Mathematics
1 answer:
BabaBlast [244]3 years ago
4 0

Answer:

505

Step-by-step explanation:

sn=2a+(n-1)d

2*5+(100-1)5

10+(99)5

505

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What is the y-intercept of y = -4/3x + 4?
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You have entered a pie baking contest. In the contest, you must make several pies for the judges to taste. You will make your fa
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x=2.5 cups are needed  for 2 pies

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8 0
2 years ago
1/6d + 2/3 = 1/4(d-2) how to solve
natita [175]
Greetings!

Solve for d.
1/6d + 2/3 = 1/4(d-2)
Distribute the Parenthesis.
1/6d + 2/3 = 1/4*d+1/4*-2
1/6d + 2/3 = 1/4d+1/4*-2/1
1/6d + 2/3 = 1/4d-2/4
Reduce.
1/6d + 2/3 = 1/4d-1/2
Add -2/3 to both sides.
(1/6d + 2/3)+(-2/3)=(1/4d-1/2)+(-2/3)
Simplify.
1/6d=1/4d-3/6-4/6
1/6d=1/4d-7/6
Add -1/4d to both sides.
(1/6d)+(-1/4d)=(1/4d-7/6)+(-1/4d)
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2/12d)-3/12d=-7/6
-1/12d=-7/6
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Hope this helps.
-Benjamin
7 0
3 years ago
In his first year, a math teacher earned $32,000. Each successive year, he
Ivan

Answer:

Step-by-step explanation:

Each successive year, he

earned a 5% raise. It means that the salary is increasing in geometric progression. The formula for determining the nth term of a geometric progression is expressed as

Tn = ar^(n - 1)

Where

a represents the first term of the sequence(amount earned in the first year).

r represents the common ratio.

n represents the number of terms(years).

From the information given,

a = $32,000

r = 1 + 5/100 = 1.05

n = 20 years

The amount earned in his 20th year, T20 is

T20 = 32000 × 1.05^(20 - 1)

T20 = 32000 × 1.05^(19)

T20 = $80862.4

To determine the his total

earnings over the 20-year period, we would apply the formula for determining the sum of n terms, Sn of a geometric sequence which is expressed as

Sn = (ar^n - 1)/(r - 1)

Therefore, the sum of the first 20 terms, S20 is

S20 = (32000 × 1.05^(20) - 1)/1.05 - 1

S20 = (32000 × 1.653)/0.05

S20 = $1057920

3 0
3 years ago
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