Answer: i dont know
Step-by-step explanation: im not shur but what to help sorry
Answer:
Heights of 29.5 and below could be a problem.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.
This means that 
There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.
Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus


Heights of 29.5 and below could be a problem.
Answer:
the answer would be A.
Step-by-step explanation:
Look for how many decimal places the decimal moved and thats how many 0's would be in your number
Given:
The system of inequalities is:


To find:
The graph of the given system of inequalities.
Solution:
We have,


The related equations are:


Table of values for the given equations is:

0 1 -3
3 0 3
Plot (0,1) and (3,0) and connect them by a straight line to get the graph of
.
Similarly, plot (0,-3) and (3,3) and connect them by a straight line to get the graph of
.
The signs of both inequalities are ">". So, the boundary line is a dotted line and the shaded region or each inequality lie above the boundary line.
Therefore, the graph of the given system of inequalities is shown below.
Answer:
h = 10 m
Step-by-step explanation:
The formula for area of a trapezoid is
A = (1/2)(B + b)h where B is the bottom base, b is the top base, and h is the height.
We are given B = 16, b = 14, and A = 15, plug those values in and simplify
150 = (1/2)(16 + 14)(h)
150 = (1/2)(30)(h)
150 = (15)h (half of 30 is 15)
10 m = h (divide both sides by 15 to isolate h)