a trapezoide has an area of 150 square meters. If the bases are 14 meters and 16 meters, what is the height of the trapezoid

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

6 0

Answer:

h = 10 m

Step-by-step explanation:

The formula for area of a trapezoid is

A = (1/2)(B + b)h where B is the bottom base, b is the top base, and h is the height.

We are given B = 16, b = 14, and A = 15, plug those values in and simplify

150 = (1/2)(16 + 14)(h)

150 = (1/2)(30)(h)

150 = (15)h (half of 30 is 15)

10 m = h (divide both sides by 15 to isolate h)

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Read 2 more answers

Q1.Simplify:

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$\textbf{(i)}\\\\\{1^3 +2^3 \} \times \left(\dfrac 13 \right)^2\\\\=(1+8) \left(\dfrac 19 \right)\\\\=9\left(\dfrac 19 \right)\\\\=1\\\\$

$\textbf{(ii)}\\\\\{5^{-1}\times 4^{-1}\}^2\\\\=\left(5^{-1} \right)^2 \times \left(4^{-1} \right)^2~~~~~~~~~~~;[(ab)^m = a^mb^m]\\\\=5^{-2}\times 4^{-2}~~~~~~~~~~~~~~~~~~~~;[(a^m)^n = a^{mn}]\\\\=\dfrac 1{5^2} \times \dfrac 1{4^2}~~~~~~~~~~~~~~~~~~~~~~;\left[a^{-m} = \dfrac 1{a^m},~ a\neq 0 \right]\\\\=\dfrac{1}{400}\\\\=0.0025\\\\$

$\textbf{(iii)}\\\\\left\{ \left(\dfrac 13 \right)^{-2} \times \left( \dfrac 12 \right)^{-2}\right\}\div \left(\dfrac 14 \right)^{-3}\\\\\\=\left( \dfrac 13 \times \dfrac 12 \right)^{-2} \div\left(4^{-1}\right)^{-3}\\\\\\=\left(\dfrac 16 \right)^{-2} \div 4^3\\\\\\=\left(6^{-1} \right)^{-2}\div 4^3\\\\\\=6^2 \div 4^3\\\\\\=36\div 64\\\\\\=\dfrac{9}{16}\\\\\\=0.5625$