Answer:
about 409.946 Hz
Step-by-step explanation:
The multiplier of frequency is (√(tension multiplier))/(length multiplier), so is ...
(√1.25)/1.2 = (5/12)√5 ≈ 0.931695
So, the longer, tighter string will have the lower frequency of about ...
0.931695×440 Hz ≈ 409.946 Hz
Answer:
yes
Step-by-step explanation:
Answer:
True
Step-by-step explanation:
When covariance matrices of corresponding class are identical and diagonal matrix and their class probability is same then the class is normally distributed and its discriminant functions are linear.
In the scientific value of
5.893 x 10n. The standard value is 0.00005893 what is n?
To better illustrate this
phenomenon, we can explain it further under the rules of scientific notation.
For example.
<span><span>
1. </span><span> 3 x 10^3 = 3 x
100 = 300</span></span>
<span><span>2. </span><span> 3 x 10^-3 = 3 x
0.001 = 0.003</span></span>
Solution:
0.00005893 = 5.893 x 0.00001 =
5.893 x 10^-5
n= ^-5
Answer:
Step-by-step explanation:
-1 1 3 5 7 9 11
That's the answer. If you need a method or a formula, that's a little harder.
L = a + (n - 1)*d
a = -1
L = 11
n = 7
or n is the hard part. If you have 5 means, then you have 6 spaces. So n must be 7 in all
11 = -1 + (7 - 1)*d add 1 to both sides. Combine the brackets
11+1 = -1+1+ 6*d
12 = 6d divide by 6
12/6 = d
2 = d
What this tells you is that each term has 2 added to it to get to the next one.
