Which direction does the graph of the equation shown below open? y2+16y-4x+4=0

2 answers:

5 0

We are asked to determine the opening of the graph of the given equation y² + 16y - 4x + 4= 0. To answer this problem, we need to transform the equation into the standard form where all variable y and variable x are in opposite side such as shown below:
y² + 16y - 4x + 4 = 0
y² + 16y = 4x - 4
y² + 16y + 64 = 4x - 4 +64
(y + 8)² = 4x + 60

Then, the graph opens to the right.

____ [38]4 years ago

3 0

the answer for apex is "right"

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Mkey [24]

So.. let's say ∡AGB and ∡BGC are say "a" units wide, and ∡CGD and ∡DGE are "b" units wide

notice the picture below

all angles added up together, will make up just a flat line, or 180°

now, notice in the picture, the ∡BGD is really just " a + b " wide, notice the green angle in the picture of ∡BGD, well, we know what a + b is