Any perpendicular line has a negative reciprocal slope. So your slope would be 2. The. You would have the equation : y=2x+b. You would then replace the coordinate (5,6) with x and y on your line to solve for b. Your equation would be : y=2x-4
Answer:
Step-by-step explanation:
Let 
. We have that 
if and only if we can find scalars 
such that 
. This can be translated to the following equations:
1. 
2.
3. 
Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for 
and check if the third equationd is fulfilled.
Case (2,6,6)
Using equations 1 and 2 we get
whose unique solutions are 
, but note that for this values, the third equation doesn't hold (3+2 = 5 
6). So this vector is not in the generated space of u and v.
Case (-9,-2,5)
Using equations 1 and 2 we get
whose unique solutions are 
. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.
Answer:
Step-by-step explanation:
First substitue the coordinates to the equation so
x=9, y=2
you would get
2=-3/7(9) + b
we put b because we are trying to find the new slope
multiply the two numbers above
2=-3/6/7 + b
subtract the whole number from both sides
b= 5/6/7
in equation would be
y= -3/7 + 5/6/7
Let me know if there is an error.
Answer: Qualititative, Nominal and Categorical
Explanation:
The variable is qualitative since it does not involve numerical data (i.e. numbers). Rather we're dealing with names or labels.
Since names or labels are involved, and there isn't really inherent order to them, we consider this qualitative data to be nominal.
We can also consider it categorical since each label is a category.
The answer to your question is 2.3
