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3 years ago

Find the probability that a randomly selected group of five adults will contain all men. Give your answer as a reduced fraction.

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

7 0

Assuming the probability of selecting one man is 1/2 and independent events,

$p = (\frac 1 2)^5 = \frac{1}{32}$

Answer: 1/32

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The data in the tables below were collected from first year students at a community college. The variable is "number of credit c

Oliga [24]

Solution :

It is given that P(x) is said to be complete or proper probability distribution if it satisfies the following two ways :

1. $P(x) \geq 0$

2. $\sum_z P(x) = 1$

Now consider,

$\sum_z P(x) = 1$

⇒ $P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)=1$

⇒ $0.61+T+0.14+0.01+0.01+0.03=1$

⇒ $0.8+T=1$

⇒ $T=1-0.8$

= 0.2

Therefore, the value of T is 0.2

Thus, option (c) is correct.

7 0

3 years ago

Mr.giarmo left for work at 7:15

seraphim [82]

The answer is 7:40am 15 plus 25

6 0

3 years ago

Total surface area of a cube is 1014cm^2. It's volume will be :

rewona [7]

Answer:

$V=2197\ cm^3$

Step-by-step explanation:

<u>Surface Area and Volume of a Cube</u>

Given a cube of side length a, the surface area is:

$A = 6a^2$

The volume is calculated as:

$V=a^3$

It's given the surface area of a cube:

$A=1014\ cm^2$

We can find the side length a by solving for a:

$\displaystyle a=\sqrt{\frac{A}{6}}$

$\displaystyle a=\sqrt{\frac{1014}{6}}$

$\displaystyle a=\sqrt{169}$

a = 13 cm

Now compute the volume:

$V=13^3$

$\boxed{V=2197\ cm^3}$

Answer: a) 2197 cm^3

5 0

3 years ago

The volume of a gold bar is 100cm cubed

Dahasolnce [82]

Answer:

1930g

Step-by-step explanation:

Mass = density × volume

Mass = 19.3×100 = 1930g

6 0

3 years ago

20 points, please answer which option is correct

Natalija [7]

Answer:

Step-by-step explanation:

its the only negative whilst others are positive

5 0

2 years ago

Read 2 more answers