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3 years ago

2 3/7÷2/3×3/4 Please help I need the homework done by tomorrow

1 answer:

4 0

I dont know if the "2" at the beginning is involved and is getting multiplied (ex. 2x3/7)
but if it is,i would sat 27/28 is the answer

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I need to know how to find the mean for 77,82,87,85,32,78?

lys-0071 [83]

Answer:

73.5

Step-by-step explanation:

To find the mean, sum the data and divide by the amount of data

mean = $\frac{77+82+87+85+32+78}{6}$

= $\frac{441}{6}$ = 73.5

6 0

3 years ago

Read 2 more answers

Find a polynomial P(x) with real coefficients having a degree 4, leading coefficient 4, and zeros 3-i and 4i.

Alisiya [41]

now, this polynomial has roots of 3-i and 4i, namely 3 - i and 0 + 4i.

let's bear in mind that a complex root never comes all by her lonesome, her sibling is always with her, the conjugate, so if 3 - i is there, 3 + i is also coming along, likewise if 0 + 4i is there, her sibling 0 - 4i is also there.

$\bf \begin{cases} x=3-i\implies &x-3+i=0\\ x=3+i\implies &x-3-i=0\\ x=4i\implies &x-4i=0\\ x=-4i\implies &x+4i=0 \end{cases}\\\\[-0.35em] ~\dotfill\\\\ (x-3+i)(x-3-i)(x-4i)(x+4i)=\stackrel{y}{0} \\[2em] \underset{\textit{difference of squares}}{[(x-3)+i][(x-3)-i]}\underset{\textit{difference of squares}}{[x-4i][x+4i]}=0$

$\bf [(x-3)^2-i^2][x^2-(4i)^2]=y\implies [(x-3)^2-(-1)][x^2-(4^2i^2)]=0 \\[2em] [(x-3)^2-(-1)][x^2-(16(-1))]=0\implies [(x-3)^2+1][x^2+16]=0 \\[2em] [(x^2-6x+9)+1][x^2+16]=y\implies (x^2-6x+10)(x^2+16)=0 \\\\\\ x^4-6x^3+10x^2+16x^2-96x+160=0 \\\\\\ x^4-6x^3+26x^2-96x+160=0 \\\\\\ \stackrel{\textit{multiplying both sides by 4}}{4(x^4-6x^3+26x^2-96x+160)=4(0)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 4x^4-24x^3+104x^2-384x+640=y~\hfill$

3 0

3 years ago

Find the slope of the line

lakkis [162]

Answer:

Step-by-step explanation:

Rise / Run

= 4/2

= 2

8 0

3 years ago

Read 2 more answers

The rectangular coordinates of a point are given. Find the polar coordinates (r,theta) of this point with theta expressed in r

alexandr402 [8]

Answer:}

In polar coordinates P is

P ( 12 ; 2.618 )

Step-by-step explanation:

The point (ectangular coordinates)

P ( -6√3 ; 6 ) P ( x ; y )

Polar coordinates P ( r ; θ )

x = r cos θ

y = r sin θ r > 0 and 0 ≤ θ ≤ 2π

Then

r = √ (x)² + (y)² r = √(36)²*3 +( 36)² r = √144

r = 12 (hypothenuse module always positive)

The point P ( -6√3 ; 6 ) is in second cuadrant between 90° and 180°

angle between r and horizontal axis x is equal to θ

tan α = l.opp/ l.adj. tan θ = y/x tan θ = - 6 /6√3

tan α = - 1/√3

Then α = 180⁰ - 150⁰ = 30⁰ or θ = 150⁰

to express that value in radians we have :

1 π radian = 180⁰ ⇒ 3,1416 radians = 180⁰

x ?? = 150⁰

x = radians

Finally the point is P ( 12 ; 2.618 )

6 0

3 years ago

the height of the water in a fish pod is 42.5 inches . water is being drained from the pond at a rate of 3.75 inches per minute

Olenka [21]

Answer:

The height of water after 3 minutes of drain is 31.25 inches .

Step-by-step explanation:

Given as :

The initial height of water in a fish pod = i = 42.5 inches

The rate of drain of water = r = 3.75 inches per min

Let The height of water after 3 min = f inches

The time taken for water drain = t = 3 minutes

<u>Now, According to question</u>

∵ In 1 minute , The water decreases = 3.75 inches

∴ In 3 minute ,The water decreases = 3.75 inches × 3

I.e In 3 minute ,The water decreases = 11.25 inches

Now, The height of water after 3 min = initial height of water - the decrease height of wate

f = i - 11.25 inches

Or, f = 42.5 inches - 11.25 inches

or, f = 31.25 inches

So, The height of water after 3 min = f = 31.25 inches

Hence, The height of water after 3 minutes is 31.25 inches Answer

6 0

3 years ago