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kodGreya [7K]
3 years ago
13

Pls help meeee! and show work and explain so I can understand better.

Mathematics
1 answer:
olchik [2.2K]3 years ago
3 0

Answer:

806 meters

Step-by-step explanation:

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If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
erma4kov [3.2K]

Answer:

\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}

Step-by-step explanation:

Given

5 tuples implies that:

n = 5

(h,i,j,k,m) implies that:

r = 5

Required

How many 5-tuples of integers (h, i, j, k,m) are there such thatn\ge h\ge i\ge j\ge k\ge m\ge 1

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed:  This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

^{n}C_r => ^{n + 4}C_5

^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}

^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}

Expand the numerator

^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}

<u><em>Solved</em></u>

6 0
3 years ago
CAN I PLEASE GET HELP ON THIS ASAP!!
mart [117]
The answer is 21

252 / 12 = 21

I hope this helped :)
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3 years ago
Write the ratio 6.5:3.25 in the form n:1
Ket [755]

Answer:

2:1

Step-by-step explanation:

8 0
3 years ago
What is the length of PR​
guajiro [1.7K]

Answer:

9

Step-by-step explanation:

This is because 21/7 is 3. So, you use the scale factor of 3 to divide 27/3 to get x which is 9.

3 0
3 years ago
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Function g is a transformation of the parent exponential function. Which statements are true about function g?
Elan Coil [88]

Answer:

function g is positive over (-∞, ∞)

function g has a y-intercept of (0,4)

function g decreasing over the interval (-∞, 0)

Step-by-step explanation:

3 0
3 years ago
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