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2 years ago

8n+7=31 what does n equal

Mathematics

2 answers:

shusha [124]2 years ago

7 0

Answer: n = 3

Step-by-step explanation:

oksano4ka [1.4K]2 years ago

6 0

Answer:

Step-by-step explanation:

take the 7 and minus it from 31 then divide 8 from 31

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Can anyone help out with these two questions?

nikitadnepr [17]

To find f(3), plug x = 3 in f(x),
∴ f(3) = 3(3)+1 = 9+1 = 10
Therefore, the ordered pair is (3,10)

For second one,
plug x = 10 in f⁻¹(x),

f⁻¹(10) = 10-1/3 = 9/3 = 3

Therefore, the ordered pair is (10,3)

5 0

2 years ago

One car takes half a minute to complete a circuit.

Liono4ka [1.6K]

Answer:

7 laps

Step-by-step explanation:

5 0

3 years ago

A speed limit is 35 mph. A car is travelling 10 mph over the speed limit. I’d that a sum of 0

max2010maxim [7]

Answer:

The car is going 45 mph

Step-by-step explanation:

Since the speed limit is 35 mph and the car is 10 mph over the speed, we can add them to find out how fast the car is going. We can solve 35+10 which will give us 45. So it is not a sum of 0 but instead a sum of 45.

(hope this helped)

5 0

3 years ago

Read 2 more answers

What is the approximate area of the shaded sector in the circle shown below?

Veronika [31]

Answer:

11.45

Step-by-step explanation:

8 0

3 years ago

The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

Answer-

The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%

Solution-

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

5 0

3 years ago