Answer:
Point A(9, 3)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Coordinates (x, y)
- Functions
- Function Notation
- Terms/Coefficients
- Anything to the 0th power is 1
- Exponential Rule [Rewrite]:
- Exponential Rule [Root Rewrite]:
<u>Calculus</u>
Derivatives
Derivative Notation
Derivative of a constant is 0
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Chain Rule]: ![\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%20%3Df%27%28g%28x%29%29%20%5Ccdot%20g%27%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<em />
<em />
<em />
<em />
<em />
<u>Step 2: Differentiate</u>
- [Function] Rewrite [Exponential Rule - Root Rewrite]:
![\displaystyle y = x^{\frac{1}{2}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%20%3D%20x%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
- Basic Power Rule:
![\displaystyle y' = \frac{1}{2}x^{\frac{1}{2} - 1}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%27%20%3D%20%5Cfrac%7B1%7D%7B2%7Dx%5E%7B%5Cfrac%7B1%7D%7B2%7D%20-%201%7D)
- Simplify:
![\displaystyle y' = \frac{1}{2}x^{-\frac{1}{2}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%27%20%3D%20%5Cfrac%7B1%7D%7B2%7Dx%5E%7B-%5Cfrac%7B1%7D%7B2%7D%7D)
- [Derivative] Rewrite [Exponential Rule - Rewrite]:
![\displaystyle y' = \frac{1}{2x^{\frac{1}{2}}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%27%20%3D%20%5Cfrac%7B1%7D%7B2x%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D)
- [Derivative] Rewrite [Exponential Rule - Root Rewrite]:
![\displaystyle y' = \frac{1}{2\sqrt{x}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%27%20%3D%20%5Cfrac%7B1%7D%7B2%5Csqrt%7Bx%7D%7D)
<u>Step 3: Solve</u>
<em>Find coordinates of A.</em>
<em />
<em>x-coordinate</em>
- Substitute in <em>y'</em> [Derivative]:
![\displaystyle \frac{1}{6} = \frac{1}{2\sqrt{x}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B1%7D%7B6%7D%20%3D%20%5Cfrac%7B1%7D%7B2%5Csqrt%7Bx%7D%7D)
- [Multiplication Property of Equality] Multiply 2 on both sides:
![\displaystyle \frac{1}{3} = \frac{1}{\sqrt{x}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B1%7D%7B3%7D%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%7Bx%7D%7D)
- [Multiplication Property of Equality] Cross-multiply:
![\displaystyle \sqrt{x} = 3](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%7Bx%7D%20%3D%203)
- [Equality Property] Square both sides:
![\displaystyle x = 9](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%20%3D%209)
<em>y-coordinate</em>
- Substitute in <em>x</em> [Function]:
![\displaystyle y = \sqrt{9}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%20%3D%20%5Csqrt%7B9%7D)
- [√Radical] Evaluate:
![\displaystyle y = 3](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%20%3D%203)
∴ Coordinates of A is (9, 3).
Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Derivatives
Book: College Calculus 10e
Answer:
26/15
Step-by-step explanation:
See attached image.
Answer:
-54
Step-by-step explanation:
27−34
=27−81
=−54
Answer:
s=3
Step-by-step explanation:
33/3=11
Answer:
150 degrees
Step-by-step explanation:
Graphing the complex number we see the angle terminates in the second quadrant. This means the argument, the angle, will be between 90 degrees and 180 degrees.
So if we create a right triangle with that point after graphing it. We see the height of that triangle is 5 because that is the imaginary part. The base of that triangle has length
. The problem is this doesn't give us any part of the angle we want, but it does give us the complementary of the part of the angle that is in second quadrant.
Let's find the complementary angle.
So the opposite side of the complementary angle is 5.
The adjacent side of the complementary angle is
.
![\tan(\theta)=\frac{5}{5\sqrt{3}}](https://tex.z-dn.net/?f=%5Ctan%28%5Ctheta%29%3D%5Cfrac%7B5%7D%7B5%5Csqrt%7B3%7D%7D)
![\tan(\theta)=\frac{1}{\sqrt{3}}](https://tex.z-dn.net/?f=%5Ctan%28%5Ctheta%29%3D%5Cfrac%7B1%7D%7B%5Csqrt%7B3%7D%7D)
![\theta=\tan^{-1}(\frac{1}{\sqrt{3}})](https://tex.z-dn.net/?f=%5Ctheta%3D%5Ctan%5E%7B-1%7D%28%5Cfrac%7B1%7D%7B%5Csqrt%7B3%7D%7D%29)
![\theta=30](https://tex.z-dn.net/?f=%5Ctheta%3D30)
So 90-30=60.
The answer therefore 60+90=150.