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BartSMP [9]
4 years ago
9

Consider the statement: 4-3+5=-6+8+4. This is a mathematically correct sentence. Is the stenence true or false? Explain how you

know.
Mathematics
1 answer:
olganol [36]4 years ago
6 0

If 4 - 3 + 5 = -6 + 8 + 4 is a mathematically correct statement, then both sides should end up with the same number:

4 - 3 + 5 = -6 + 8 + 4     <em>Original statement.</em>

1 + 5 = -6 + 8 + 4     <em>You can do this in any order, but I start by doing the 4 - 3.</em>

6 = -6 + 8 + 4     <em>Finish simplifying the left side.</em>

6 = 2 + 4     <em>Combine the -6 and 8.</em>

6 = 6     <em>Finish simplifying the right side.</em>

Because both sides are equal to each other, the sentence must be true.

Therefore, the sentence is true because when simplified, the statement is 6 = 6.

<em>Hope this helps! :)</em>

<u><em>EDIT: Just incase anyone is curious, both this way and the way the other guy used both work, as they both prove that both sides are equal.</em></u>

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What is the length of DE ?
Salsk061 [2.6K]

Answer:

A. 6

Step-by-step explanation:

On triangle ZYX divide each side by 3 to get 4-4-3. Then multiple each side by 2, to get 8-8-6. That would mean DE is 6.

4 0
3 years ago
Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
  • Symmetry: \forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x
  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

5 0
3 years ago
Which of the following is a quadratic function?
Fudgin [204]

Answer:A is a quadratic function

Step-by-step explanation:

A quadratic function is one of the form f(x) = ax2 + bx + c, where a, b, and c are numbers with a not equal to zero. If you solve the function, y= 2x^2+x-6.

6 0
3 years ago
Plz help me I you can♡︎
masya89 [10]

Answer:

Step-by-step explanation:

all you have to do is pick to points from the graph and input then in <u>y1-y2 </u>

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3 0
3 years ago
Read 2 more answers
3/10x - 1 = 3/4
Allisa [31]
First you make -1 and 3/4 have a common denominator. 1 has a fraction of 1/1 so times four it is 4/4. Then you add on both sides in order  to isolate x and you get 3/10x = 7/4.

Then you isolate x by multyiplying the reciprocal of 3/10 on both sides, 10/3.
3/10 and 10/3 cancel out and you get an answer of x = 70/4.

You could then simplify it to get 35/6 by finding a greasted common multiple of 12 and 70 which is 2 and dividing both by 2 to get a simpilier answer.

So the answer is x = 35/6
4 0
3 years ago
Read 2 more answers
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