1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kodGreya [7K]
3 years ago
5

Coach Hayes goes to a sporting goods store to purchase mouth guards for his team. There are two packages of mouth guards availab

le for him to select: ten Adidas mouth guards for $14.50 and fifteen Nike mouth guards for $21.45. Coach Hayes needs to buy 60 mouth guards. In total, how much money with he save by purchasing 60 mouth guards from the cheapest package?
Mathematics
2 answers:
Eva8 [605]3 years ago
4 0

Answer:

12h - 33 = 99

Step-by-step explanation:

ahrayia [7]3 years ago
4 0
The answer is 85.8 because the cheapest package is the nike one and if you multiply that times 4 which will give you 60 mouth gaurds, the amount of money will be 85.8
You might be interested in
Hey can someone help me out thank! :D ITS DUE TODAY!!! :p
worty [1.4K]

Answer:

4

Step-by-step explanation:

 

Write an equation of a line in slope-intercept form for the given conditions.

-intercept and -intercept

(Hint: Write the intercepts as ordered pairs)

4 0
3 years ago
Read 2 more answers
The scatterplot shows the average miles per gallon versus the age, in years, of a car.
densk [106]

Answer:

The sign would remain the same.

It would have the same value.

ED2021

5 0
2 years ago
The first drop down: (x-12),(x-80), (80-x), (12-x)
Mice21 [21]

Answer:x=12 and 68$

Step-by-step explanation:

4 0
3 years ago
Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen
SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ =  \frac{4!}{1! (4 - 1 )!} × \frac{6!}{2! (6 - 2 )!}

                                                                            = \frac{4!}{(3)!} × \frac{6!}{2! (4)!}

                                                                            = \frac{4.3!}{(3)!} × \frac{6.5.4!}{2! (4)!}

                                                                            = 4 × \frac{6.5}{2.1! }

                                                                            = 4 × 15 = 60

Total Number of possibility = ¹⁰C₃ = \frac{10!}{3! (10-3)!}

                                                        = \frac{10!}{3! (7)!}

                                                        = \frac{10.9.8.7!}{3! (7)!}

                                                        = \frac{10.9.8}{3.2.1!}

                                                        = 120

So, probability = \frac{60}{120} = \frac{1}{2} = 0.5

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility  = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility   = ⁴C₀ × ⁶C₃

                   =  \frac{4!}{0! (4 - 0)!} × \frac{6!}{3! (6 - 3)!}

                   = \frac{4!}{(4)!} × \frac{6!}{3! (3)!}

                   = 1 × \frac{6.5.4.3!}{3.2.1! (3)!}

                   = 1× \frac{6.5.4}{3.2.1! }

                   = 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = \frac{80}{120} = \frac{8}{12} = 0.66

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility  = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility   = ⁴C₂ × ⁶C₁

                   =  \frac{4!}{2! (4 - 2)!} × \frac{6!}{1! (6 - 1)!}

                   = \frac{4!}{2! (2)!} × \frac{6!}{1! (5)!}

                   = \frac{4.3.2!}{2! (2)!} × \frac{6.5!}{1! (5)!}

                   = \frac{4.3}{2.1!} × \frac{6}{1}

                   = 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility   = ⁴C₃ × ⁶C₀

                   =  \frac{4!}{3! (4 - 3)!} × \frac{6!}{0! (6 - 0)!}

                   = \frac{4!}{3! (1)!} × \frac{6!}{(6)!}

                   = \frac{4.3!}{3!} × 1

                   = 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = \frac{100}{120} = \frac{10}{12} = 0.83

3 0
2 years ago
The half-life of a certain radioactive material is 83 hours. An initial amount of the material has a mass of 67 kg. Write an exp
Anvisha [2.4K]

Answer:

  • Initial amount of the material is 67 kg
  • Hal-life is 83 hours

<u>The required equation is:</u>

  • m(x) = 67 * (1/2)^{x/83}, where m- remaining amount of the radioactive material, x - number of hours

<u>After 5 hours the material remains:</u>

  • m(5) = 67 * (1/2)^{5/83} = 64.260 (rounded)
4 0
2 years ago
Other questions:
  • Will give brainliest geometry basics help
    13·2 answers
  • Has slope 5/2 and passes through (4,-1)
    13·1 answer
  • What power can you write to represent the volume of a cube shown? write the power as an expression with a base and an exponent a
    8·1 answer
  • If v1 = (2,-5) and v2 = (4,-3), then the angle between the two vectors is _________. Round your answer to two decimal places.
    7·1 answer
  • What
    6·2 answers
  • A line has slope 5/6 and y–intercept −3.
    6·1 answer
  • How is -6.1 wrote in fraction form​
    6·2 answers
  • I need help with this PLEASE!!
    9·1 answer
  • (1, 2) and (3, -2).<br><br> writing equations in slope intercept form
    10·2 answers
  • If a circle has a radius of 8 units what is its circumference
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!