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Otrada [13]
3 years ago
7

What is the value of s in the equation 4(2s − 1) = 7s + 12? (4 points)

Mathematics
2 answers:
avanturin [10]3 years ago
6 0

Answer:

B. 16

Step-by-step explanation:

Solve for s:

\longrightarrow 4(2s - 1) = 7s + 12

Expand out terms of the left hand side:

\longrightarrow 8s - 4 = 7s + 12

Subtract 7 s from both sides:

\longrightarrow (8s - 7s) - 4 = (7s - 7s) + 12

8s - 7s = s:

\longrightarrow s - 4 = (7s - 7s) + 12

7s - 7s = 0:

\longrightarrow s - 4 = 12

Add 4 to both sides:

\longrightarrow s + (4 - 4) = 4 + 12

4 - 4 = 0:

\longrightarrow s = 12 + 4

12 + 4 = 16:

\longrightarrow s = 16

notka56 [123]3 years ago
3 0

Answer:

B) 16

8s-4=7s+12

s-4=12

s=16

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-30=5(x+1) x=? Solve for X
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Answer:

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Step-by-step explanation:

-30=5(x+1)

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-35=5x

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3 years ago
Alisha has a $15,000 car loan with a 6 percent interest rate that is compounded annually. How much will she have paid at the end
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3 years ago
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In Exercise 4, find the surface area of the solid<br> formed by the net.
Fittoniya [83]

Answer:

3. 150.72 in²

4. 535.2cm²

Step-by-step Explanation:

3. The solid formed by the net given in problem 3 is the net of a cylinder.

The cylinder bases are the 2 circles, while the curved surface of the cylinder is the rectangle.

The surface area = Area of the 2 circles + area of the rectangle

Take π as 3.14

radius of circle = ½ of 4 = 2 in

Area of the 2 circles = 2(πr²) = 2*3.14*2²

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Area of the rectangle = L*W

width is given as 10 in.

Length (L) = the circumference or perimeter of the circle = πd = 3.14*4 = 12.56 in

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Surface area of net = Area of the 2 circles + area of the rectangle

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4. Surface area of the net (S.A) = 2(area of triangle) + 3(area of rectangle)

= 2(0.5*b*h) + 3(l*w)

Where,

b = 8 cm

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S.A =  2(27.6) + 3(160)

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6 0
3 years ago
Suppose that the perimeter a rectangle is 54 feet, and the length is 13 feet more than the width. Find the width ractangle, in f
Vesnalui [34]

Answer:7feet

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54=2(w+13)+2w

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8 0
3 years ago
How do I do this help
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3 years ago
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