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2 years ago

What is the product of the sum of 20 and 10 and the difference of 20 and 10

Mathematics

2 answers:

DanielleElmas [232]2 years ago

7 0

Answer:

300

Step-by-step explanation:

(20+10)·(20-10)

1. Simplify: 30·10

2. Multiply: 300

Llana [10]2 years ago

5 0

Answer:

300

Step-by-step explanation:

(20+10) • (20-10)

= 30 • 10

= 300

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Factor completely -2x^3 + 6x^2

Bumek [7]

We can factor a -2 and an x^2 out of this using GCF.

<h3><u>-2x^2(x - 3) is what we're left with, and is the fully factored form.</u></h3>

3 0

3 years ago

If you want brainiest and thanks and 10 points please help me with this question... Evaluate a+(−b) where a=4 and b=2

Vesna [10]

Answer:

a + (-b) = 4 + (-2) = 4 - 2 = 2

6 0

3 years ago

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Troyanec [42]

Answer:

the second statement is true

Step-by-step explanation:

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2 years ago

Read 2 more answers

How many radians is -135°

Yuri [45]

Answer:

-3/4 pi radians

Step-by-step explanation:

<em>180° is 1 pi radian</em>

Hence, -<em>135° = -135/180 pi radians</em>

= -0.75 pi radians

= -3/4 pi radians

6 0

3 years ago

Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

7 0

3 years ago