Jon has $5,000 to invest in a savings account that has interest compounded annually. If he wants his money to double in eight ye
ars, what percent must the interest rate be on the account?
1 answer:
<span>log(1 + rate) = {log(total) -log(Principal)} ÷ Years
</span>
<span>log(1 + rate) = {log (10,000) - log (5,000)} / 8
</span><span>log(1 + rate) = {4 - 3.6989700043} / 8
</span>
<span><span>log(1 + rate) = 0.3010299957
</span>
/ 8
</span><span><span><span>log(1 + rate) = 0.0376287495
</span>
</span>
</span>
Now we take 10 and raise it to the power of <span>0.0376287495
10 ^ </span>0.0376287495 =
<span>
<span>
<span>
1.0905077327
</span>
</span>
</span>
We subtract one:
<span>
<span>
.0905077327
then multiply it by 100
</span></span><span><span>9.05077327</span>%
Source:
http://www.1728.org/compint2.htm
</span>
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