Use the substitution method to solve the system of equations. Choose the correct ordered pair. Y=5x-17 y=x+3

During a math game, a team kept track of their answers. The following diagram describes the number of answers they got right to

juin [17]

Where’s the diagram ?

8 0

3 years ago

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The prism below is packed with no gaps between the cube that measure 1/4 ft. What is the volume, in cubic feet of the right rect

Yuki888 [10]

Answer: 1/2

First you do 4/4 times 4/4. Which is equal to 1. Then, you multiply by 2/4 to get 1/2.

5 0

3 years ago

Will you help me i am have a lot of trouble on this on

vodka [1.7K]

Answer:

A = 18 cm²

Step-by-step explanation:

The volume (V) of a prism is calculated as

V = area of base (A) × height

Here V = 216 cm³ and h = 12 cm , then

A × 12 = 216 ( divide both sides by 12 )

A = 18 cm² ← area of base

7 0

3 years ago

If the quadratic formula is used to find the solution set of 3x2 + 4x - 2 = 0, what are the solutions?

7nadin3 [17]

Answer:

$x=\frac{-2}{3} \pm \frac{\sqrt{10}}{3}$

Step-by-step explanation:

Compare $ax^2+bx+c$ to $3x^2+4x-2$ .

We have $a=3,b=4,c=-2$ .

The quadratic formula is for solving equations of the form $ax^2+bx+c=0$ and is $x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$ .

So we are going to plug in our values in that formula to find our solutions,x.

If you want to notice it in parts you can.

Example I might break it into these parts and then put it in:

Part 1: Evaluate $b^2-4ac$

Part 2: Evaluate $-b$

Part 3: Evaluate $2a$

------Let's do these parts.

Part 1: $b^2-4ac=(4)^2-4(3)(-2)=16-12(-2)=16+24=40$ .

This part 1 is important in determining the kinds of solutions you have. It is called the discriminant. If it is positive, you have two real solutions. If it is negative, you have no real solutions (both of the solutions are complex). If it is 0, you have one real solution.

Part 2: $-b=-4$ since $b=4$ .

Part 3: $2a=2(3)=6$ .

Let's plug this in:

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

or in terms of our parts:

$x=\frac{\text{Part 2} \pm \sqrt{\text{Part 1}}}{\text{Part 3}}$

$x=\frac{-4 \pm \sqrt{40}}{6}$

40 itself is not a perfect square but it does contain a factor that is. That factor is 4.

So we are going to rewrite 40 as $4 \cdot 10$ .

$x=\frac{-4 \pm \sqrt{4 \cdot 10}}{6}$

$x=\frac{-4 \pm \sqrt{4} \cdot \sqrt{10}}{6}$

$x=\frac{-4 \pm 2\cdot \sqrt{10}}{6}$

I'm going to go ahead and separate the fraction like so:

$x=\frac{-4}{6} \pm \frac{2 \cdot \sqrt{10}}{6}$

Now I'm going to reduce both fractions:

$x=\frac{-2}{3} \pm \frac{1 \cdot \sqrt{10}}{3}$

$x=\frac{-2}{3} \pm \frac{\sqrt{10}}{3}$

6 0

3 years ago

Help me and i will give you 50 poings

Elis [28]

Answer:

Ok so 1. I am in AP Calculus BC and I legit just fully learned how to do exponents (I had a rough year in algebra 1 lol) so don't feel bad. And 2. It's really simple. When you multiply exponents you so just add them so x^2 * x^3=x^5. This makes sense visually since x^3 is x*x*x and x^2 is x*x and when you multiply that out you get x*x*x*x*x. Division is also pretty simple and all you have to do is subtract them. (There is a reason for this but its not important but I'll explain it anyways. Basically when you divide it is the same thing as multiplying by a negative exponent so x^3 / x^2 = x.) When you have multiple variables all you have to do is combine like terms so if you have something like xy^2*xy^4 you would get (x^2)(y^6). As for your problems, here:

8vx

63ce

21a^2

48xw^2

30m^3n^2

120a^2c^2x^3

2n

8x

3wx

4ac^2

2wx^2

2a^2c

5a

3

4c

8ab

7bc

8ac

I hope this helps!

(Also, double check those when you put them in please lol)

4 0

3 years ago

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