Answer: 3.6
Step-by-step explanation:
(Not the best at math but I am an above level student)
C= pi x diameter
C= pi x 1.205
C= 3.7
Answer:
405
Step-by-step explanation:
To find sample size, use the following equation, where n = sample size, za/2 = the critical value, p = probability of success, q = probability of failure, and E = margin of error.
The values that are given are p = 0.84 and E = 0.03.
You can solve for the critical value which is equal to the z-score of (1 - confidence level)/2. Use the calculator function of invNorm to find the z-score. The value will given with a negative sign, but you can ignore that.
(1 - 0.9) = 0.1/2 = 0.05
invNorm(0.05, 0, 1) = 1.645
You can also solve for q which is 1 - p. For this problem q = 1 - 0.84 = 0.16
Plug the values into the equation and solve for n.
Round up to the next number, giving you 405.
Answer:
C. 25h – 5
Step-by-step explanation:
5(6h - 1) - 5h = 30h - 5 - 5h = 25h - 5
Answer:
1. -4(6)= -24
2.-21-8= -29
3. 121-4 =117
4. -6(5) =-30
5. -10(-9)= 90
6. (-5)7= -35
7. (-5)8= -40
8. -30(5)= -150
9. 20(-6)= -120
10. -14(6)= -84
11. (-13)2 = -26
12. –7(15) = -105
13. -3(4) = -12
14. 7(-3) = -21
15. 3(-3) = -9
16. -2(-10) = 20
17. (-5)(-3)(4) = 60
18. -3(-3)(4)= 36
19. -3(-5) = 15
20. 5(-3) = -15
21. 7(-5)(4) = -140
22. -2(-5)(-3)= -30
23. – 10(-3)=30
24. -21-3= -24
Explanation:
We have followed the rules in adding and subtracting negative as well as positive values on the number line.
When adding two negative values, the result is a negative value.
When adding a negative and positive value, the result is either a positive or negative value depending on if the negative value is bigger or smaller than the positive value
When multiplying two negative values, the result is a positive value
When multiplying one negative and one positive value, the result is a negative value
To make you understand addition and subtraction of negative and positive numbers better, let us use a simple analogy. Assuming you are owing five oranges(-5) and you are only able to give two oranges(+2), you will still be owing 3 oranges(-3). Assuming also that you are owing 6 oranges(-6) and you are able to give 8 oranges(+8), you would have given excess oranges and would be owed two oranges(+2). Hence the results above.
