Answer:
(x + 6, y + 0), 180° rotation, reflection over the x‐axis
Step-by-step explanation:
The answer can be found out simply , a trapezoid has its horizontal sides usually parallel meanwhile the vertical sides are not parallel.
The horizontal parallel sides are on the x-axis.
Reflection over y- axis would leave the trapezoid in a vertical position such that the trapezoid ABCD won't be carried on the transformed trapezoid as shown in figure.
So option 1 and 2 are removed.
Now, a 90 degree rotation would leave the trapezoid in a vertical position again so its not suitable again.
In,The final option (x + 6, y + 0), 180° rotation, reflection over the x‐axis, x+6 would allow the parallel sides to increase in value hence the trapezoid would increase in size,
180 degree rotation would leave the trapezoid in an opposite position and reflection over x-axis would bring it below the Original trapezoid. Hence, transformed trapezoid A`B`C`D` would carry original trapezoid ABCD onto itself
54:84___(÷2)
27:42___(÷3)
9:14
Answer:
y = (1/3)x^3 +4x + c . . . . . for some constant c
Step-by-step explanation:
The anti-derivative of x^n is (x^(n+1))/(n+1). Applying this rule to each of the terms in dy/dx, we get ...
y = (1/3)x^3 + 4x
There may be an added constant as well, conventionally represented by "c".
y = (1/3)x^3 +4x +c
Step-by-step explanation:
incomplete question
you didnt give any choice to choose from
prime factor stuff.. 32 = 8*4 = (4*2)*(2*2) = (2*2*2)*(2*2)
3 √(2*2*2*2*2*x*x*x*x*z) = 3 √(2²*2²*2*x²*x²*z)
It's a square root so move one of each pair outside the radical.
3*2*2*x*x √(2*z)
12x² √(2z)