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3 years ago

Please answer 2 and 3 !!

Mathematics

1 answer:

Usimov [2.4K]3 years ago

6 0

(2) So we know Ethan uses 1/4 cup of milk for his cake. And if he needs to make 3 times the amount of 1 cake, he'll make 3 cakes today. So we multiply the amount of cakes (3) by the amount of milk needed (1/4)

3 * 1/4 = 3/4

Ethan will need 3/4 cups of milk.

(3) We know Isabella need's 2/5 of a gallon of the food to make 1 gallon.

She want's to make 5 gallons, so like the other problem, we multiply the amount of gallons (5) by the amount of food needed (2/5):

5 * 2/5 = 10/5 = 2/1.

Isabella will need 2 gallons of food.

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The number of defective circuit boards coming off a soldering machine follows a Poisson distribution. During a specific ten-hour

Alexus [3.1K]

Answer:

a) the probability that the defective board was produced during the first hour of operation is $\frac{1}{10}$ or 0.1000

b) the probability that the defective board was produced during the last hour of operation is $\frac{1}{10}$ or 0.1000

c) the required probability is 0.2000

Step-by-step explanation:

Given the data in the question;

During a specific ten-hour period, one defective circuit board was found.

Lets X represent the number of defective circuit boards coming out of the machine , following Poisson distribution on a particular 10-hours workday which one defective board was found.

Also let Y represent the event of producing one defective circuit board, Y is uniformly distributed over ( 0, 10 ) intervals.

f(y) = $\left \{ {{\frac{1}{b-a} }\\\ }} \right _0$ ; ( a ≤ y ≤ b ) $_{elsewhere$

= $\left \{ {{\frac{1}{10-0} }\\\ }} \right _0$ ; ( 0 ≤ y ≤ 10 ) $_{elsewhere$

f(y) = $\left \{ {{\frac{1}{10} }\\\ }} \right _0$ ; ( 0 ≤ y ≤ 10 ) $_{elsewhere$

Now,

a) the probability that it was produced during the first hour of operation during that period;

P( Y < 1 ) = $\int\limits^1_0 {f(y)} \, dy$

we substitute

= $\int\limits^1_0 {\frac{1}{10} } \, dy$

= $\frac{1}{10} [y]^1_0$

= $\frac{1}{10} [ 1 - 0 ]$

= $\frac{1}{10}$ or 0.1000

Therefore, the probability that the defective board was produced during the first hour of operation is $\frac{1}{10}$ or 0.1000

b) The probability that it was produced during the last hour of operation during that period.

P( Y > 9 ) = $\int\limits^{10}_9 {f(y)} \, dy$

we substitute

= $\int\limits^{10}_9 {\frac{1}{10} } \, dy$

= $\frac{1}{10} [y]^{10}_9$

= $\frac{1}{10} [ 10 - 9 ]$

= $\frac{1}{10}$ or 0.1000

Therefore, the probability that the defective board was produced during the last hour of operation is $\frac{1}{10}$ or 0.1000

no defective circuit boards were produced during the first five hours of operation.

probability that the defective board was manufactured during the sixth hour will be;

P( 5 < Y < 6 | Y > 5 ) = P[ ( 5 < Y < 6 ) ∩ ( Y > 5 ) ] / P( Y > 5 )

= P( 5 < Y < 6 ) / P( Y > 5 )

we substitute

$= (\int\limits^{6}_5 {\frac{1}{10} } \, dy) / (\int\limits^{10}_5 {\frac{1}{10} } \, dy)$

$= (\frac{1}{10} [y]^{6}_5) / (\frac{1}{10} [y]^{10}_5)$

= ( 6-5 ) / ( 10 - 5 )

= 0.2000

Therefore, the required probability is 0.2000

4 0

3 years ago

Will mark brainliest

poizon [28]

Answer:

u = 4

v = 18

Step-by-step explanation:

in a parallelogram, diagonals bisect each other into two equal segments so we can do the following:

2u+2 = 5u-10

subtract '2u' from each side to get:

2 = 3u-10

add 10 to each side to get:

12 = 3u

12/3 = u

u = 4

To solve for 'v':

v/3 = 6

multiply each side by 3 to get:

v = 18

7 0

2 years ago

Convert the numeral to a numeral in base ten. 2331nine

BaLLatris [955]

Answer:

Step-by-step explanation:

Converting 2331 to base 10.

2*93=1458

3*92=243

3*91=27

1*90=1

Adding all to get Ans=172910

4 0

4 years ago

Performance-enhancing drugs affect an individual by which of the following?

mel-nik [20]

D. Give performers an unfair advantage

Let’s talk about option A; Drugs that athletes take (for e.g. steroids) they INCREASE athletes muscle mass & endurance. They look bigger & muscular than a normal natural athlete.
Option B is also incorrect because there is no drugs that are legal in sports
Option C - It increase the athletes performance and your extremely energetic. You are doing what an natural cannot do in a short period of time.
SO OPTION D - It’s unfair to the natural ones

8 0

2 years ago

Write and solve a story problem about gathering three kinds of vegetables. Use 10 partners.

Nata [24]

Answer:

Cameron and Rebecca are organizing a lunch for their friends. Within the dishes to be served, they will prepare a tomato, carrot and broccoli salad. The number of tomatoes and carrots are 10-partners and the total amount of vegetables is 12. If we increase the number of broccoli by three and decrease the number of tomatoes by two, the amount of tomatoes and broccoli will also be 10-partners. What is the number of tomatoes, carrots and broccoli bought by Cameron and Rebecca?

<u>Cameron and Rebecca purchased 7 tomatoes, 3 carrots and 2 broccoli.</u>

Step-by-step explanation:

Number of tomatoes = x

Number of carrots = 10 - x

Number of broccoli = y

System of Equations:

x + 10 - x + y = 12

y = 12 - 10

y = 2

x - 2 + y + 3 = 10 (If we increase the number of broccoli by three and decrease the number of tomatoes by two, the amount of tomatoes and broccoli will also be 10-partners)

x + 1 + y = 10

x + y = 9

y = 9 - x

Substitution of y:

x + 10 - x + y = 12

x + 10 - x + 9 - x = 12

-x + 19 = 12

-x = 12 - 19

x = 7 ⇒ 10 - x = 3

<u>Cameron and Rebecca purchased 7 tomatoes, 3 carrots and 2 broccoli.</u>

Note: Same answer to question 14280211, answered by me today.

6 0

3 years ago