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deff fn [24]
3 years ago
9

Please answer 2 and 3 !!

Mathematics
1 answer:
Usimov [2.4K]3 years ago
6 0

(2) So we know Ethan uses 1/4 cup of milk for his cake. And if he needs to make 3 times the amount of 1 cake, he'll make 3 cakes today. So we multiply the amount of cakes (3) by the amount of milk needed (1/4)

3 * 1/4 = 3/4

Ethan will need 3/4 cups of milk.

(3) We know Isabella need's 2/5 of a gallon of the food to make 1 gallon.

She want's to make 5 gallons, so like the other problem, we multiply the amount of gallons (5) by the amount of food needed (2/5):

5 * 2/5 = 10/5 = 2/1.

Isabella will need 2 gallons of food.

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Solve for x. <br> 7/8 = x/16
Kitty [74]

Answer:

X=16*7/8= 14. by multiplying. 16 *7/8

7 0
3 years ago
Read 2 more answers
Shane started FFA with a pig that weighed 120 pounds. After six weeks her pig gained 30% in weight. what is the new weight of sh
grigory [225]
First, we must figure out how much weight the pig gained and then add that number to the pig’s initial weight.

To figure out how much weight the pig gained, we must find 30% of 120.

Because 30% = 0.3, 30% of 120 = 0.3 * 120 ( the word of indicates multiplication in mathematics).

0.3 * 120 = 36

Therefore, the pig gained 36 pounds.

To find the pig’s new weight, we must add 36 pounds to the pig’s original 120 pound weight.

36 + 120 = 156

Therefore, the new weight of Shane’s pig is 156 pounds.

Hope this helps!
8 0
3 years ago
HELPPP Pleaseeee
Mariana [72]

Answer:

1,749

8,349

Step-by-step explanation:

We can multiply 6,600 by 1.265 to get 8,349. To get the percentage all we have to do is multiply 6,600 by .265 and get 1,749.

Hope this helps

3 0
2 years ago
Simplify 7y exponent 2- y exponent 2=
GuDViN [60]
7y^2 - y^2 = 6y^2

hope it helps
3 0
3 years ago
Read 2 more answers
A ball is launched upward from a height 40 feet above ground level. The ball’s height at t seconds is given by -16t^2=128=40 .
Nesterboy [21]

Answer:

The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec

Step-by-step explanation:

<u><em>The correct question is</em></u>

A ball is launched upward from a height 40 feet above ground level. the ball's height at t seconds is given by h(t)=-16t^2+128t+40 At what time(s) will the ball be at 100 feet?

we have

h(t)=-16t^{2}+128t+40

so

For h(t)=100 ft

substitute in the equation and solve for x

-16t^{2}+128t+40=100

-16t^{2}+128t-60=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^{2}+128t-60=0

so

a=-16\\b=128\\c=-60

substitute in the formula

x=\frac{-128(+/-)\sqrt{128^{2}-4(-16)(-60)}} {2(-16)}

x=\frac{-128(+/-)\sqrt{12,544}} {-32}

x=\frac{-128(+/-)112} {-32}

x=\frac{-128(+)112} {-32}=0.5

x=\frac{-128(-)112} {-32}=7.5

therefore

The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec

7 0
4 years ago
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