All categories

3 years ago

How do plants most commonly break large rocks into smaller pieces

2 answers:

6 0

There are several ways for plants to break large rocks into smaller pieces, such as :

- Plant Grows roots into the rocks and crack it from the inside
- they can leave insulate surrounding rocks from extreme temperatures
- Plants' seeds can contain acidic substance that will slowly deteriorate the rocks when it falls

galina1969 [7]3 years ago

4 0

Plants most commonly break large rock into smaller pieces by having the plant root grow into cracks in rocks. The plant root from below the surface grows and that's how they break rocks into pieces.

You might be interested in

How do protons, neutrons, and electrons differ in charge?

Semenov [28]

Answer: Protons have a positive charge. Electrons have a negative charge. The charge on the proton and electron are exactly the same size but opposite. Neutrons have no charge.

Explanation:

7 0

2 years ago

Determine which equations you would use to solve the following problem: Calculate the amount of heat needed to change 20.0 g of

Inessa [10]

Answer:

Q = 4019.4 J

Explanation:

Given data:

Mass of ice = 20.0 g

Initial temperature = -10°C

Final temperature = 89.0°C

Amount of heat required = ?

Solution:

specific heat capacity of ice is 2.03 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 89.0°C - (-10°C)

ΔT = 99°C

Q = 20.0 g ×2.03 J/g.°C × 99°C

Q = 4019.4 J

3 0

3 years ago

A balloon is filled with 1 mole of helium gas at 100 kPa of pressure and a

mylen [45]

Answer:

B) 0.025 $m^{3}$

Explanation:

Solution of the problem is in picture attached,

3 0

3 years ago

Given these reactions, X ( s ) + 1 2 O 2 ( g ) ⟶ XO ( s ) Δ H = − 668.5 k J / m o l XCO 3 ( s ) ⟶ XO ( s ) + CO 2 ( g ) Δ H = +

qwelly [4]

Answer: The $\Delta H^o_{rxn}$ for the reaction is -1052.8 kJ.

Explanation:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

$X(s)+\frac{1}{2}O_2(g)+CO_2(g)\rightarrow XCO_3(s)$ $\Delta H^o_{rxn}=?$