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Mandarinka [93]
3 years ago
10

A water bottle is cooled to -115c. What is the new pressure

Chemistry
2 answers:
seraphim [82]3 years ago
8 0
.........................................................................
Fudgin [204]3 years ago
7 0

Answer:

129

Explanation:

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Think about your morning from when you wake up until you arrive at school. Describe the forms of energy you encounter or use dur
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Answer:

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3 0
2 years ago
How many grams of water vapor (H2O) are in a 10.2 liter sample at 0.98 atmospheres and 26ÁC? Show all work used to solve this pr
klio [65]
The answer is 7.33 g.

<span>To calculate this, we will use the the ideal gas law:
PV = nRT
where
P - pressure of the gas,
V - volume of the gas,
n - amount of substance of gas,
R - gas constant,
T - temperature of the gas.</span>

Since the amount of substance of gas (n) can be expressed as mass (m) divided by molar mass (M), then:

PV = RTm/M

It is given:

P = 0.98 atm

V = 10.2 l

T = 26°C = 299.15 K 

R = 0.082 l atm/Kmol (gas constant)

M (H2O) = 2Ar(H) + Ar(O) = 2*1 + 16 = 2 + 16 = 18g

m = ?

Since PV = RTm/M, then:

m = PVM/RT

m = 0.98 · 10.2 · 18 / 0.082 · 299.15 = 179.928/24.5303 = 7.33 g

6 0
3 years ago
Determine the concentration of a solution (M) made by dissolving 18.8 g of sodium chloride (NaCl) in 750.0 mL of solution.
Viefleur [7K]

Answer:

0.429 M

Explanation:

To find the molarity, you need to (1) convert grams to moles (using the molar mass), then (2) convert mL to L, and then (3) calculate the molarity (using the molarity ratio).

(Step 1)

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

18.8 grams NaCl               1 mole
--------------------------  x  ------------------------  =  0.322 moles NaCl
                                     58.443 grams

(Step 2)

1,000 mL = L

 750.0 mL                1 L
------------------  x  -----------------  =  0.7500 L
                            1,000 mL

(Step 3)

Molarity (M) = moles / volume (L)

Molarity = 0.332 moles / 0.7500 L

Molarity = 0.429 M

5 0
1 year ago
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