That acid rain has lowered the ph of a particular lake to ph 5.0. the hydroxide ion concentration of this lake is
1 × 10^-9 mol of hydroxide ions per liter of lake water
pH + pOH = 14
pOH = 14 - 5
pOH = 9.00
pOH = -log [OH⁻]
[OH⁻] = 10^-pOH
[OH⁻] = 
mol
Therefore,
the hydroxide ion concentration of this lake is 1 × 10^-9 mol
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Answer:
The answer to your question is letter B
Explanation:
A.) 2 AgCl + Na2S ⟶ 2 Ag2S + 2 NaCl
Reactants Elements Products
2 Ag 4
2 Cl 2
2 Na 2
1 S 2
This reaction is unbalanced
B.) 2 AgCl + Na2S ⟶ Ag2S + 2 NaCl
Reactants Elements Products
2 Ag 2
2 Cl 2
2 Na 2
1 S 1
This reaction is balanced
C.) AgCl + Na2S ⟶ 2 Ag2S + 2 NaCl
Reactants Elements Products
1 Ag 4
1 Cl 2
2 Na 2
1 S 2
This reaction is unbalanced
D.) 2 AgCl + 2 Na2S ⟶ Ag2S + NaCl
Reactants Elements Products
2 Ag 4
2 Cl 1
4 Na 1
2 S 1
This reaction is unbalanced
Answer:
0.5 mol HCl
Explanation:
2.5 mol/L *0.200 L = 0.5 mol NaOH
NaOH + HCl ---> NaCl + H2O
from reaction 1 mol 1 mol
given 0.5mol x mol
x= 0.5*1/1= 0.5 mol HCl
