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rosijanka [135]
3 years ago
6

103-39= how do you borrow from zero?

Mathematics
1 answer:
IRINA_888 [86]3 years ago
4 0
You barrow form the next place which is the hundreds place. (See picture)

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Can anyone solve this please it's an urgent ​
Vinil7 [7]

Answer:

missing element is 6

Step-by-step explanation:

Given

f(x) = x³ - 2 ( substitute x = 2 )

f(2) = 2³ - 2 = 8 - 2 = 6 ← missing element

ordered pair is (2, 6 )

6 0
3 years ago
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Find the equation for intercept x 4 and y -7​
nadezda [96]

Answer:

y = \frac{-7x}{4} - 14

Step-by-step explanation:

The equation used to find the equation for a line with two intercepts is called point slope form. y - y_{1} = m(x - x_{1}) , where y_{1} and x_{1} are the intercept points and m is the slope.

However, we need the slope to use this formula.

Use m = \frac{y_{1} - y_{2} }{x_{1} - x_{2}}

m = \frac{y_{1} - y_{2} }{x_{1} - x_{2}}

m = \frac{((0) - (7))}{((4) - (0))}

m = \frac{-7}{4}

y - y_{1} = m(x - x_{1})

y - ( -7 ) = m ( x - ( 4 ) )

y - ( -7 ) = -7/4 ( x - ( 4 ) )

y + 7 = -7/4 ( x + 4 )

y + 7 = \frac{-7(x+4)}{4}

y + 7 = \frac{-7x-28}{4}

y + 7 = \frac{-7x}{4} - 7

y + 7 = \frac{-7x}{4} - 7 - 7

y = \frac{-7x}{4} - 14

8 0
3 years ago
Which of the following problems would NOT have a solution?
Vika [28.1K]
The last one I think
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19. passes through (1, 4) and (-1, 1)
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Ok so the answer to this was a bit tricky but it is 1,8
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AleksandrR [38]
Differentiate both sides with respect to x

\frac{d}{dx}(x^{\frac{1}{2}} + y^{\frac{1}{2}}) = \frac{d}{dx}(1)\\\\ \frac{1}{2x^{\frac{1}{2}}} + \frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = 0\\\\\frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = -\frac{1}{2x^{\frac{1}{2}}}\\\\\frac{1}{2\sqrt{y}}\frac{dy}{dx} = -\frac{1}{2\sqrt{x}} \\\\\frac{dy}{dx} = -\frac{1}{2\sqrt{x}} \times 2\sqrt{y}\\\\\frac{dy}{dx} = -\frac{\sqrt{y}}{\sqrt{x}} \\\\\boxed{\bf{y'= -\frac{\sqrt{y}}{\sqrt{x}}}}
5 0
3 years ago
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