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rosijanka [135]
3 years ago
6

103-39= how do you borrow from zero?

Mathematics
1 answer:
IRINA_888 [86]3 years ago
4 0
You barrow form the next place which is the hundreds place. (See picture)

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Bianca reads 3/4 of a page of a book each minute. She has 25 pages left to read. How many pages will she read in 5 1/2 minutes?​
Viktor [21]

Answer:

Bianca reads a page of a book in 1 ÷ (3/4) = 1 x (3/4) = 4/3 minutes;

We have 5 1/2 = 11/2 minutes;

She reads (11/2) ÷ (4/3) = (11/2) x (3/4) = 33 /8 = 4 1/8 pages;

Step-by-step explanation:

3 0
3 years ago
Use the figure below to find the value of y and each angle shown.
igomit [66]

5y - 16 + 3y + 20 = 180 degrees

Combine like terms on the left side

8y + 4 = 180

Subtract 4 from both sides.

8y = 176

Divide both sides by 8

y = 22

Plug 22 into y for each angle.

3y + 20 = 3(22) + 20 = 66 + 20 = 86 degrees

5y - 16 = 5(22) - 16 = 110 - 16 = 94

The angle opposite 5y - 16 also equals 94 because they are vertical angles.

The angle opposite of 3y + 20 also equals 86 because they are vertical angles

6 0
3 years ago
Y=(2x-3)^5(2-x^4)^3 differentiate the function please
BARSIC [14]
\bf y=(2x-3)^5(2-x^4)^3\\\\
-------------------------------\\\\
\cfrac{dy}{dx}=\stackrel{\textit{product rule}}{[5(2x-3)^4\cdot 2(2-x^4)3]~~+~~[(2x-3)^5[3(2-x^4)^2(-4x^3)]]}
\\\\\\
\cfrac{dy}{dx}=10(2x-3)^4(2-x^4)^3~~-~~12x^3(2x-3)^5(2-x^4)^2
\\\\\\
\cfrac{dy}{dx}=\stackrel{\textit{common factor}}{2(2x-3)^4(2-x^4)^2}~[5(2-x^4)-6x^3(2x-3)]
\\\\\\
\cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2~[10-5x^4-12x^4+18x^3]
\\\\\\
\cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2(10-17x^4+18x^3)
5 0
3 years ago
Davin ran the marathon in 4 3/5 hours. Melba ran the marathon in 226 minutes. After she crossed the finish line, Melba waited fo
emmasim [6.3K]
(by far the most painful question all day) 226 mins = 3.77 hours 4 3/5 hours = 4.6 hours 4.6- 3.77 = 0.83 hours 0.83 hours = 49.8 mins = 2988 seconds.
7 0
3 years ago
9 and 5/12 - 3 and 2/3
lana [24]
Recall to always convert the mixed fractions to "improper" fractions first,

\bf \stackrel{mixed}{9\frac{5}{12}}\implies \cfrac{9\cdot 12+5}{12}\implies \stackrel{improper}{\cfrac{113}{12}}
\\\\\\
\stackrel{mixed}{3\frac{2}{3}}\implies \cfrac{3\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{11}{3}}\\\\
-------------------------------\\\\
\cfrac{113}{12}-\cfrac{11}{3}\impliedby \textit{clearly our LCD is 12}\implies \cfrac{113-(4)11}{12}
\\\\\\
\cfrac{113-44}{12}\implies \cfrac{69}{12}\implies 5\frac{9}{12}
5 0
3 years ago
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