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Mashutka [201]
3 years ago
13

Determine the molecular mass ratio of two gases whose rates of effusion have a ratio of 16 : 1.

Chemistry
1 answer:
Usimov [2.4K]3 years ago
8 0
Answer is: <span>the molecular mass ratio of two gases is 1 : 256.
</span>rate of effusion of gas1 : rate of effusion of gas = 16 : 1.<span>
rate of effusion of gas1 = 1/√M(gas1).
rate of effusion of gas2 = 1/√M(gas2).
rate of effusion of gas1 = rate of effusion of gas2 </span>· 16<span>.
</span>1/√M(gas1) = 1/√M(gas2) · 16 /².
<span>1/M(gas1) = 1/M(gas2) </span>· 256.
<span>M(gas1) </span>· 256 = M(gas2).<span>

</span>
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