Answer:
HCl is the correct answer
I’m pretty sure the answer would not be C) Human Resources.
Answer:
0.168mL of the 1.0M KI solution must be added
Explanation:
The PbI₂ is in equilibrium with water as follows:
PbI₂ ⇄ Pb²⁺ + 2I⁻
Where Ksp is:
Ksp = 1.4x10⁻⁸ = [Pb²⁺] / [I⁻]²
As molarity of Pb²⁺ is 0.11M:
1.4x10⁻⁸ = [0.11M] / [I⁻]²
1.27x10⁻⁷ = [I⁻]²
3.57x10⁻⁴M = [I⁻]
Thus, to precipitate all Pb²⁺ you need to add 3,57x10⁻⁴M of I⁻. As volume of the solution is 470.0mL = 0.47L, you need to add:
0.47L * (3,57x10⁻⁴moles / L) = 1.68x10⁻⁴ moles of I⁻ = Moles of KI.
That comes from the 1.0M KI. You need to add:
1.68x10⁻⁴ moles of KI * (L / 1.0 mol) = 1.68x10⁻⁴L =
<h3>0.168mL of the 1.0M KI solution must be added</h3>
Answer:
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Answer:
specific heat = 0.951 j/g·°C
Explanation:
Heat flow equation => q = m·c·ΔT
q = heat flow = 4817 joules
m = mass in grams = 140 grams Aluminum
c = specific heat = ?
ΔT = Temperature Change in °C = 98.4°C - 62.2°C = 36.2°C
q = m·c·ΔT => c = q/m·ΔT = 4817j/(140g)(36.2°C) = 0.951 j/g·°C