well the wind can blow any direction depending on the ocean. the ocean is going North and is really wavy. there will be a lot of wind and going North,
Ok so the PH for each solution will be
<span>1.) 1.638
2.) 5.2
3.) 12.524
This is found using the formula: </span> pH<span> = - log [H</span>3O+].
And the pOh for each one will be
<span>1.) 12.362
2.) 8.8
3.) 1.4763
This is found by the formula </span>pOH = -log10[OH-<span>]
</span>Hope this is useful
Answer:
(a) -49.9 kJ/mol;
(b) To the right;
(c) 34.6 kJ/mol
Explanation:
(a) For this reaction, since it's at equilibrium and standard states, we know that we can apply the equation:

Substituting the given variables:

(b) Notice that this reaction is spontaneous, since
. This means reaction spontaneously proceeds to the right side. Besides, K > 1, this means products dominate over reactants, so reaction proceeds to the right.
(c) Given the expression of the formation constant, we can use the same expression to calculate the reaction quotient at non-standard conditions:
![Q_f = \frac{[Ni(NH_3)_6]^{2+}}{[Ni^{2+}][NH_3]^6} = \frac{0.010}{0.0010\cdot 0.0050^6} = 6.4\cdot 10^{14}](https://tex.z-dn.net/?f=Q_f%20%3D%20%5Cfrac%7B%5BNi%28NH_3%29_6%5D%5E%7B2%2B%7D%7D%7B%5BNi%5E%7B2%2B%7D%5D%5BNH_3%5D%5E6%7D%20%3D%20%5Cfrac%7B0.010%7D%7B0.0010%5Ccdot%200.0050%5E6%7D%20%3D%206.4%5Ccdot%2010%5E%7B14%7D)
Now, notice that
. In this case, we have an excess of the products, this means reaction will shift to the let left to restore the equilibrium.
Calculate:

Answer:contact forces or transfer energy(not sure)
Explanation:
Answer:
* is a soft,silvery metal that reacts violently with water