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3 years ago

If a = b, then a - c = b - c. This is the _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ property of equality.

Mathematics

2 answers:

inessss [21]3 years ago

4 0

Answer:

The correct answer is Subtraction property of the equality.

Step-by-step explanation:

Let's recall that it's possible to perform the same operation on each side of an equivalent linear equation without changing the equality.

That's why we can add, subtract, multiply (same non-zero number) and divide (same non-zero number) the same number to each side of a linear equation and, that operation,gives us an equivalent equation .

In this particular case, we are subtracting c at both sides of the equation and this a representation of the Subtraction property of the equality.

Whitepunk [10]3 years ago

3 0

Answer:

Associative Property

Step-by-step explanation:

Associative property involves computations that has to do with regrouping of quantities. That is simply the technique employed there.

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3 years ago

Write an

Helga [31]

Answer:

Since the Line is Perpendicular

m.m'=-1

The line

y=x+8

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2 years ago

ALGEBRA QUESTION PLS HELPS

cluponka [151]

The value of x is –7.

Solution:

Given expression:

$$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}$

Let us factor $x^2+4x+3$ .

$x^2+4x+3=(x+1)(x+3)$

Substitute this in the fraction.

$$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

To make the denominator same, multiply and divide the first term by (x +1).

$$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

Denominators are same, you can add the fractions.

$$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

$$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}$

Cancel the common term in the numerator and denominator.

$$\frac{x+7}{x+1} \cdot \frac{1}{x+1}$

Multiply the fractions.

$$\frac{x+7}{(x+1)^2}$

$$\frac{x+7}{x^2+2x+1}$

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$$\frac{x+7}{x^2+2x+1}=0$

Do cross multiplication.

$${x+7}=0\times (}{x^2+2x+1})$

Any number or variable multiplied by 0 gives 0.

$${x+7}=0$

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$${x+7-7}=0-7$

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The value of x is –7.

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