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loris [4]
3 years ago
6

What is the equation of the exponential graph shown? Please help :'(

Mathematics
2 answers:
shutvik [7]3 years ago
7 0
Exponential functions fit the template
y = a*b^x
where 'a' and b are fixed values

The value of 'a' is the y intercept. In this case, it is 100 since (0,100) is on the curve. This is the part where the graph crosses the y axis. So a = 100.

The value of b takes a bit of work to find. We'll plug a = 100, x = 1 and y = 50 into the equation shown above. Why x = 1 and y = 50 you might ask? Well the point (1,50) appears to be on the graph as well.

So plugging those three items into the equation leads to
y = a*b^x
50 = 100*b^1
50 = 100*b
50/100 = 100*b/100 ... divide both sides by 100
1/2 = b
b = 1/2 
b = 0.5

So the equation is y = 100*(1/2)^x which can be written as y = 100*(0.5)^x

The value of b = 1/2 = 0.5 indicates that we multiply each previous result by 1/2 = 0.5 to get the next result. This is another way of saying "divide each result by 2 to get the next"

Eg: 
100 ---> 50 ---> 25 etc
ladessa [460]3 years ago
3 0

Answer: f(x) = 100/(2ˣ) cause your points are (0, 100), (1, 50), (2, 25), and (3, 12.5) so it's decaying by half everytime the x-value gets bigger. The graph starts at 100 and decays by 1/2 everytime making the equation f(x) = 100/(2ˣ).

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What is the measure of the angle that is complementary to the given angle?
katrin2010 [14]

Answer:

36°

Step-by-step explanation:

Complementary angles: The measure of two angles adds up to 90°.

90° - 54° = 36°

8 0
2 years ago
if mn is a midsegment to abc find the values of x and y. this is the only time im gonna use this so here's 50 points
Sliva [168]
X would equal 3 and y would equal 7

thanks for the points to mate
7 0
2 years ago
On each round, Ann and Bob each simultaneously toss a fair coin. Let Xn be the number of heads tossed in the 2n flips which occu
CaHeK987 [17]

Answer:

P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}

Step-by-step explanation:

In a coin toss the  probability of tossing a head is 0.5 (50% head/50% tails)

If n is the number of rounds and 2n the number of coins tossed (one for each player), the probability of having m heads tossed is:

R=\frac{2n!}{m!*(2n-m)!}

R is the number of cases (combination of coins tossed) that gives a m number of heads. Each case has a probability of P_{case}=0.5^{2n} so:

P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}

<u>For example, to toss 4 heads in 5 rounds: </u>

  • n=5
  • 2n=10
  • m=4

P=\frac{10!}{4!*(10-4)!}*0.5^{10}

P=\frac{10*9*8*7*6!}{4!*6!}*0.5^{10}

P=\frac{10*9*8*7}{4!}*0.5^{10}

P=\frac{10*9*8*7}{4!}*0.5^{10}=0.205

8 0
3 years ago
A random sample of 102 full-grown lobsters had a mean weight of 16 ounces and a standard deviation of 3.4 ounces. Construct a 98
pshichka [43]

Answer:

The best point estimate for a confidence interval estimating the population μ is 16 ounces.

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The best point estimate for a confidence interval estimating the population μ is

The sample mean, so 16 ounces.

T interval

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 102 - 1 = 101

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 101 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.98}{2} = 0.99. So we have T = 2.36

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.36\frac{3.4}{\sqrt{102}} = 0.79

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 16 - 0.79 = 15.21 ounces

The upper end of the interval is the sample mean added to M. So it is 16 + 0.79 = 16.79 ounces

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

4 0
2 years ago
Order the numbers from least to greatest: -6, 5, -5, 6, 0
Arturiano [62]
-6,-5,0,5,6 that is the order from least to greatest
3 0
3 years ago
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