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Dmitry_Shevchenko [17]
4 years ago
6

What’s the answer? Please help!

Mathematics
2 answers:
Thepotemich [5.8K]4 years ago
7 0
Answer A would the final answer
gregori [183]4 years ago
5 0

Answer:

A

Step-by-step explanation:

a^3 is a * a * a, b^2 is b * b, so we can write that in the numerator.

\frac{a * a * a * b * b}{a^2b}

a^2 is a * a. So we can change that in the denominator.

\frac{a * a * a * b * b}{a*a*b}

The denominator cancels out with part of the numerator, and leaves us with just a*b, which is ab, which is answer A.

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What is 7 times 5 to the third powder
natita [175]

Answer:

875

Step-by-step explanation:

7*5^3=875

6 0
3 years ago
A student fit the line shown below to the data in the scatter plot. Which statement about the student's line is true?
Furkat [3]

Answer:

C. It is not a good fit because there are no points on the line.

Step-by-step explanation:

In order for a line to be a good fit for a data set represented as a scatterplot, the line must follow the general trend of the data in the scatterplot. This line does not follow the general trend of the data on the scatterplot, thus option (C) is the best statement to describe the situation.

C. It is not a good fit because there are no points on the line.

8 0
3 years ago
Pls solve this qn..............ASAP<br> PLS DON'T SPAMMMMM!!
Anni [7]

Probability ( a flowering plant or fruit plant) is  \frac{13}{30} and Probability (neem plant or peepal plant) is  \frac{29}{60}.

Step-by-step explanation:

Given,

Number of neem plant = 125

Number of peepal plant = 165

Number of creppers plant = 50

Number of fruit plant = 150

Number of flowering plant = 110

To find the probability ( a flowering plant or fruit plant)

and probability ( neem or peepal)

Formula

P( A or B) = P(A) + P(B)

Probability ( a flowering plant or fruit plant) = \frac{110}{600} + \frac{150}{600}

= \frac{260}{600} = \frac{13}{30}

And,

Probability (neem plant or peepal plant) = \frac{125}{600} +\frac{165}{600}

= \frac{290}{600} = \frac{29}{60}

4 0
3 years ago
Suppose that 2 ≤ f '(x) ≤ 4 for all values of x. What are the minimum and maximum possible values of
Vesna [10]

Answer:

Step-by-step explanation:

By the Mean Value Theorem, there is at least one number, c, in the interval (1,6) such that

f'(c) = [f(6) - f(1)]/ (6 - 1)

So, f(6) - f(1) = 5f'(c).

Since 2 ≤ f'(c) ≤ 4, 10 ≤ 5f'(c) ≤ 20

So, f(6) - f(1) is between 10 and 20.  

5 0
3 years ago
Use the above image to solve the problem
iragen [17]

Answer:

64

Step-by-step explanation:

(-512)^2/3

Rule: x^a/b is the bth root of x^a

cbrt(-512^2)

cbrt(262144)

64

4 0
3 years ago
Read 2 more answers
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