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KIM [24]
3 years ago
13

Help! What's 26% of 130?

Mathematics
2 answers:
Ber [7]3 years ago
5 0

Answer:

33.8

Step-by-step explanation:

130(0.26) is the expression. Solving is simple.

Salsk061 [2.6K]3 years ago
3 0

。☆✼★ ━━━━━━━━━━━━━━  ☾

130 x 0.26 = 33.8

Have A Nice Day ❤  

Stay Brainly! ヅ  

- Ally ✧  

。☆✼★ ━━━━━━━━━━━━━━  ☾

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The diameter of a circle is 12 in. Find the circumference to the nearest tenth <br> please helppp
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Answer:

37.68in

Step-by-step explanation:

circumference = 2πr

r= radius = diameter/2 = 12/2 =6 in

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3 years ago
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Quadrant I is the answer. Both are positive coordinates
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3 years ago
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Using the segment addition postulate, which is true? What is the measure of AngleDCF? Three lines extend from point C. The space
Flura [38]

Answer:

129

Step-by-step explanation:

If three lines CD, CE and CF extend from point C, then the following addition postulate is true;

<DCE + <ECF = <DCF

If the space between line C D and C E is 75 degrees, then <DCE =  75

If the space between lines C E and C F is 54, then <ECF = 54.

Substitute the given values into the expression above will  give;

<DCF =<DCE + <ECF

<DCF  = 75+54

<DCF  = 129

Hence the measure of <DCF  is 129°

8 0
3 years ago
A research team conducted a study showing that approximately 25% of all businessmen who wear ties wear them so tightly that they
Sonbull [250]

Answer:A) 0.9866

Step-by-step explanation:

Probability of at least one tie is too tight is

Probability of tight tie 25/100

Probability of not a tight tie is 1-25/100=3/4

=1-(3/4)^15=0.9866

B)0.764

C)0.013

D)0.236

Method 2

This is binomial probability.

n=15 (number of businessmen

p=.25 (probability that a businessman wears the tie so tightly

A)

x = number of businessmen out of 15 who wears the tie so tightly

P( at least 1) = P( x >= 1) = 1-P(x=0)

P(x=0) = 15C0 (.25)^0 (.75)^(15-0) = (0.75)^15 = 0.013363

P( at least 1) = 1- 0.013363 = 0.9866

B)

P(more than 2) = P( x > 2) = 1-P( x=0)-P(x=1)-P(x=2)

P(x=0) = 15C0 (.25)^0 (.75)^(15-0) = (0.75)^15 = 0.013363

P(x=1) = 15C1 (.25)^1 (.75)^14 = 0.066817

P(x=2) = 15C2 (.25)^2 (.75)^13 = 0.155907

1-P( x=0)-P(x=1)-P(x=2) = 1 - 0.013363 - 0.066817 - 0.155907 = 0.763912

C)

P(x=0) = 15C0 (.25)^0 (.75)^(15-0) = (0.75)^15 = 0.013363

D)

P( at least 13) = P(x=13)+P(x=14)+P(x=15)

P(x=13)= 15C13 (.25)^13 (.75)^2 = 0.000001

P(x=14)= 15C14 (.25)^14 (.75)^1 = 0.000000

P(x=15)= 15C15 (.25)^15 (.75)^0 = 0.000000

P(x=13)+P(x=14)+P(x=15) = .000001+.000000+.000000 = 0.000001

4 0
4 years ago
Read 2 more answers
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