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kiruha [24]
3 years ago
11

At a restaurant the ratio of kids meal sold two adult males sold was 5 to 4 if there was 20 kids meal sold what is the combined

amount of kids and adult meal sold
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
6 0
You would have 20 kids and 16 adults
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Write each expression as an algebraic​ (nontrigonometric) expression in​ u, u > 0.
max2010maxim [7]

Answer:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

Step-by-step explanation:

We want to write the trignometric expression:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)

Take the secant of both sides:

\displaystyle \sec(\theta)=\frac{u}{10}

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}

By substitutition:

\displaystyle= \sin(2\theta)

Using an double-angle identity:

=2\sin(\theta)\cos(\theta)

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)

Simplify. Therefore:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

4 0
3 years ago
Pls help with this question I don't know the answer. Don't put wrong answers pls.
Lapatulllka [165]

Answer:

-2 I believe. because the 1st exponent would make it 9, and then you'd remove 2

Step-by-step explanation:

I hope this is correct and helpful, I tried my best! <3

7 0
3 years ago
Suppose 20 rabbits are taken to an island. the rabbit population then triples every year. the function f(x)
Zanzabum
f(x) = 20*3^xf(x) = 20*3^x

hope this helps!

p.s. can i have brainliest?
5 0
3 years ago
The hexagon GIKMPR is regular. The dashed line segments form 30 degree angles.
Gwar [14]

Answer:

The correct option is (D).

Step-by-step explanation:

It is given that GIKMPR is regular hexagon. It means it has 6 vertices.

Since the central angle is 360 degree. Therefore the central angle between two consecutive vertices is

\frac{360^{\circ} }{6}=60^{\circ}

It is given that the dashed line segments form 30 degree angles.

We have rotated the hexagon about O to map PQ to RF. Since P and R are consecutive vertices, therefore the angle between them is 60 degree.

The vertex R is immediate next to the vertex P in clockwise direction.

So if we rotate the hexagon at 60 degree clockwise about O, then we can maps PQ to RF.

360^{\circ}-60^{\circ}=300^{\circ}

Therefore we can also rotate the hexagon at 300 degree counterclockwise about O, then we can maps PQ to RF.

Therefore option D is correct.


8 0
3 years ago
Find the square root of 68.1 to the nearest hundredth
Ira Lisetskai [31]
I think that is is 8.3, but I could be incorrect!
8 0
3 years ago
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