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kiruha [24]
3 years ago
11

At a restaurant the ratio of kids meal sold two adult males sold was 5 to 4 if there was 20 kids meal sold what is the combined

amount of kids and adult meal sold
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
6 0
You would have 20 kids and 16 adults
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How do I solve for x?
notka56 [123]
Solving:
\frac{3+4x}{2} + \frac{5-x}{3} = \frac{29}{6}
Make the Least Common Multiple (2,3,6)
2,3,6\:|2
1,3,3\:|3
1,1,1\:|\underline{2*3=6}


<span>Replace denominators and resolve:
</span>\frac{3+4x}{2} + \frac{5-x}{3} = \frac{29}{6}
\frac{3(3+4x)}{6} + \frac{2(5-x)}{6} = \frac{29}{6}
Cancel the dominators
\frac{3(3+4x)}{\diagup\!\!\!\!6} + \frac{2(5-x)}{\diagup\!\!\!\!6} = \frac{29}{\diagup\!\!\!\!6}
3(3+4x) + 2(5-x) = 29
9 + 12x + 10 - 2x = 29
12x - 2x = 29 - 9 - 10
10x = 20 - 10
10x = 10
x =  \frac{10}{10}
\boxed{\boxed{x = 1}}\end{array}}\qquad\quad\checkmark


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