Answer:
12
Step-by-step explanation:
I'm not entirely sure abt this but here goes nothing
75.36 divided by 3.14 = 24
24 = diameter
radius = 12
Your answer should be 3a^2 + 5x + 9
Answer:
Use simultaneous equation for this problem
y= number of adults
x = number of children
3y + 2x = 160
y + x = 60
then we double the second equation
3y + 2x = 160
2y + 2x = 120
we cancel x by elimination
3y - 2y = 160 - 120
y = 40
Step-by-step explanation:
hope this helps
Answer:
35. 
36. 
Step-by-step explanation:
Question 35:
Given:


Plug in 2 for
and simplify. This gives,

Therefore, term 2 is 16.
Question 36:
Given:


Plug in 2 for
and simplify. This gives,

Therefore, term 2 is 77.
Answer:
Step-by-step explanation:
From the given information,
Suppose
X represents the Desktop computer
Y represents the DVD Player
Z represents the Two Cars
Given that:
n(X)=275
n(Y)=455
n(Z)=405
n(XUY)=145
n(YUZ)=195
n(XUZ)=110
n((XUYUZ))=265
n(X ∩ Y ∩ Z) = 1000-265
n(X ∩ Y ∩ Z) = 735
n(X ∪ Y) = n(X)+n(Y)−n(X ∩ Y)
145 = 275+455 - n(X ∩ Y)
n(X ∩ Y) = 585
n(Y ∪ Z) = n(Y) + n(Z) − n(Y ∩ Z)
195 = 455+405-n(Y ∩ Z)
n(Y ∩ Z) = 665
n(X ∪ Z) = n(X) + n(Z) − n(X ∩ Z)
110 = 275+405-n(X ∩ Z)
n(X ∩ Z) = 570
a. n(X ∪ Y ∪ Z) = n(X) + n(Y) + n(Z) − n(X ∩ Y) − n(Y ∩ Z) − n(X ∩ Z) + n(X ∩ Y ∩ Z)
n(X ∪ Y ∪ Z) = 275+455+405-585-665-570+735
n(X ∪ Y ∪ Z) = 50
c. n(X ∪ Y ∪ C') = n(X ∪ Y)-n(X ∪ Y ∪ Z)
n(X ∪ Y ∪ C') = 145-50
n(X ∪ Y ∪ C') = 95