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Andrej [43]
3 years ago
6

Write each expression as an algebraic​ (nontrigonometric) expression in​ u, u > 0.

Mathematics
1 answer:
max2010maxim [7]3 years ago
4 0

Answer:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

Step-by-step explanation:

We want to write the trignometric expression:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)

Take the secant of both sides:

\displaystyle \sec(\theta)=\frac{u}{10}

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}

By substitutition:

\displaystyle= \sin(2\theta)

Using an double-angle identity:

=2\sin(\theta)\cos(\theta)

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)

Simplify. Therefore:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

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Replace x with 3:

y = -3 *4^3

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What property is <br><br> 5(x+y)=5x+5y
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A rock weighs 80 g on a triple beam scale. The same rock is then gently placed inside a graduated cylinder containing 30 mL of w
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Answer:

  • 1.78 g/cm³

Step-by-step explanation:

<u>80 g rock displaces water:</u>

  • 75 ml - 30 ml = 45 ml = 45 cm³

<u>Density = mass / volume:</u>

  • d = 80 g / 45 cm³
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Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
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Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

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68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

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worty [1.4K]

Answer:

<u></u>

  • <u>53 seconds.</u>

Explanation:

The text and the model are garbled.

This is the question amended:

<em />

<em>Hyun Woo is riding a ferris wheel. H(t) models his height (in m) above the ground, t seconds after the ride starts. Here, t is entered in radians.</em>

<em>H(t) = -10 cos(2π/150 t)+10</em>

<em />

<em>When does Hyun Woo first reach a height of 16 m?</em>

<em />

<h2>Solution</h2>

<em />

When <em>Hyun Woo reaches a height of 16 m</em> the <em>model </em>states:

  • <em>16 = -10 cos(2π/150 t)+10</em>

<em />

Then you must find the lowest positive value of t that is a solution of the equation.

Solve the equation:

  • <em>16 = -10 cos(2π/150 t)+10</em>

  • 10cos(2π/150 t) = - 6

  • cos(2π/150t) = -0.6

  • 2π/150t = arccos(-0.6)

  • 2π/150t = 2.214297

  • t = 52.86s ≈ 53 s ← answer
4 0
3 years ago
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