You need to find points where the line g(x) intercepts the quadratic function f(x) in one and only one point.
Then 3x^2 + 4x -2 = mx - 5
solve 3x^2 + 4x - mx -2 + 5 = 0
3x^2 + (4 - m)x + 3 = 0
In order to there be only one solution (one intersection point) the radicand of the quadratic formula must be 0 =>
b^2 - 4ac = (4 - m)^2 - 4(3)(3) = 0
(4 - m)^2 = 24
4 - m = +/- √(24)
m = 4 +/- √(24) = 4 +/- 2√(6)
Then m, the slope of the line, may be 4 + 2√6 and 4 - 2√6
Answer:
50°
Step-by-step explanation:
Since, YW bisects angle XYZ.

2x+4y=16
x-7=-4y
4y=16-2x
<span>4y=16-2(-4y+7)
4y=16+8y-14
-4y=2
-4y/-4=2/-4
<u>y=-0,5</u>
2x=16-4(-0,5)
2x=16+2
2x/2=18/2
<u>x=9
</u>
C</span>
-4/8 i think that is right not sure tho so you might wanna wait for ohter answer
You just need to find distance between two points
d=

d=6