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e-lub [12.9K]
3 years ago
5

Two double-stranded fragments of DNA are exactly the same length. At 89°C, fragment A has completely denatured, which means that

the two strands have separated. At that temperature, fragment B is still double-stranded. How might these fragments differ to result in different denaturation temperatures?
Biology
1 answer:
deff fn [24]3 years ago
4 0

Answer:

Fragment A have low GC bonds as compared to fragment B which means there will be low number of hydrogen bonds in the double stranded fragment A as compared to fragment B.

Explanation:

Denaturation temperature depend on the presence of hydrogen bonds in the DNA strand. There are hydrogen bonds between the complementary nucleotide in the DNA. Adenine form two hydrogen bonds thymine in the complementary strand while guanine form 3 hydrogen bonds with cytosine in the complementary strand.

The reason behind denaturation at 89°C is the presence of low number of G-C hydrogen bonds so the fragment of DNA with low number of G-C bonds in the complementary strand will denature at 89 °C as compared to other fragment B which will denature at 95 °C.  

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Two organisms, AABBCCDDEE and aabbccddee, are mated to produce an F1 that is self-fertilized. If the capital letters represent d
Pie

Answer:

1/1024 is the proportion of the F2 genotypes will be recessive for all five loci

Explanation:

When crossing between both parents, all genotypes will give us 100% AaBcCcDdEe. When a self-fertilization is performed this means that it can have a cross for example of two flowers of the same plant with the genotype AaBcCcDdEe In this way, given the law of independent segregation which states that the alleles of two or more different genes are distributed in the gametes independently of each other. The proportion that at this junction the alleles are aa (1/4)  bb (1/4) cc (1/4) dd (1/4) and ee (1/4). The proportions (1/4)* (1/4)*(1/4)*(1/4)*(1/4) are multiplied, obtaining a value of 1/1024

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3 years ago
If a patient who lives in texarkana, arkansas, sees a physician for medicare part b in newark, new jersey, to which location's m
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5 0
3 years ago
Considering the same population of cats as in Part A, what is the expected frequency of each genotype (TLTL, TLTS, TSTS ) based
zaharov [31]

Answer:

P = f(TLTL) = 0,16

H = f(TLTS) = 0,48

Q = f(TSTS) = 0,36

Explanation:

Hello!

The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values ​​can vary between 0 (absent allele) and 1 (fixed allele).

The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.

In this case, let's say:

f(TL) = p

f(TS) = q

p + q = 1

Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:

TL= 0,4

TS= 0,6

Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.

P = f(TLTL)

H = f(TLTS)

Q = f(TSTS)

Also P + H + Q = 1

And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:

p^{2} = f(TLTL)

2pq = f(TSTL)

q^{2} = f(TSTS)

So, if the population is in balance:

P = p^{2}

H = 2pq

Q = q^{2}

Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:

f(TLTL) = P = p^{2} = 0,4^{2} = 0,16

f(TLTS) = H = 2pq = 2*0,4*0,6 = 0,48

f(TSTS) = Q = q^{2} = 0,6^{2} = 0,36

I hope you have a SUPER day!

6 0
3 years ago
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algol [13]

Answer:

The correct answer is - T4, and T3.

Explanation:

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PtichkaEL [24]
Chromatin is dna that makes a chromosome and chromosomes are different dna strands in a cell, sister chromatids are identical pieces of dna
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