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3 years ago

Is the polynomial t^4-7 in standard form?

Mathematics

1 answer:

VMariaS [17]3 years ago

5 0

Answer:

The polynomial $t^4-7$ is in standard form.

Step-by-step explanation:

Writing the polynomial in standard form means we have to write the terms of the polynomial by descending degree.

First writing the term with the highest or largest exponent or degree first

Then writing the terms which have lower degrees/exponents in descending order.

If there is any constant term in the polynomial, it is always written in the end.

Given the polynomial

$t^4-7$

Here:

The highest exponent is the 4, so that entire term i.e. $t^4$ is written first. Here it is also written first.

Then the next term is the constant term, and constant terms is written in the end. Here, the constant terms is also written in the end.

Therefore, the polynomial $t^4-7$ is in standard form.

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What is 6002310.583 in word form?

Pani-rosa [81]

6 002 310.583

Six million and two thousand three hundred and ten point five eight three.

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3 years ago

Complete this item. Use the definition of a polygon inscribed in a circle to help you develop a definition for a polygon inscrib

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It should be noted that a polygon that's inscribed in a circle has each vertex on the outer figure.

<h3>What is a polygon?</h3>

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2 years ago

According to the U.S. Bureau of Labor Statistics, 20% of all people 16 years of age or older do volunteer work. In this age grou

Murljashka [212]

Answer:

1. P(X≥35) = 0.0183

2. P(X≤21) = 0.0183

3. P(0.18<p<0.25) = 0.7915

Step-by-step explanation:

We have the proportion for women: pw=0.22, and the proportion for men: pm=0.19.

1. We have a sample of 140 woman and we have to calculate the probability of getting 35 or more who do volunteer work.

This is equivalent to a proportion of

$p=X/n=35/140=0.25$

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.22*0.78}{300}}\\\\\\ \sigma_p=\sqrt{0.0006}=0.0239$

We calculate the z-score as:

$z=\dfrac{p-p_w}{\sigma_p}=\dfrac{0.25-0.22}{0.0239}=\dfrac{0.03}{0.0239}=0.8198$

Then, the probability of having 35 women or more who do volunteer work in this sample of 140 women is:

$P(X>35)=P(p>0.25)=P(z>2.0906)=0.0183$

2. We have to calculate the probability of having 21 or fewer women in the group who do volunteer work.

The proportion is now:

$p=X/n=21/140=0.15$

We can calculate then the z-score as:

$z=\dfrac{p-p_w}{\sigma_p}=\dfrac{0.15-0.2}{0.0239}=\dfrac{-0.05}{0.0239}=-2.0906$

Then, the probability of having 21 women or less who do volunteer work in this sample of 140 women is:

$P(X$

3. For the sample with men and women, we use the proportion for both, which is π=0.2.

The sample size is n=300.

Then, the standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.2*0.8}{300}}\\\\\\ \sigma_p=\sqrt{0.0005}=0.0231$

We can calculate the z-scores for p1=0.18 and p2=0.25:

$z_1=\dfrac{p_1-\pi}{\sigma_p}=\dfrac{0.18-0.2}{0.0231}=\dfrac{-0.02}{0.0231}=-0.8660\\\\\\z_2=\dfrac{p_2-\pi}{\sigma_p}=\dfrac{0.25-0.2}{0.0231}=\dfrac{0.05}{0.0231}=2.1651$

We can now calculate the probabilty of having a proportion within 0.18 and 0.25 as:

$P=P(0.18$

5 0

4 years ago

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Korolek [52]

Answer:

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Step-by-step explanation:

62% ........... $144.40

100% ..........$ x

x = 144.40×100/62

= 14440/62

= $ 232.90

3 0

3 years ago

Can someone answer this soon?!?

Sever21 [200]

First get all the terms on the same side:

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Now solve using the quadratic formula which is:

$\frac{-b±\sqrt{b^2 - 4ac} }{2a}$

Plug in the values:

$\frac{-7± \sqrt{49-4(1)(-4)} }{2}$

So the answer is:

$\frac{-7 ± \sqrt{65} }{2}$

6 0

3 years ago