It costs $5 to get into the fair and then costs $3 for every ride I go on.
1 answer:
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Answer:
See explanation
Step-by-step explanation:
In ΔABC, m∠B = m∠C.
BH is angle B bisector, then by definition of angle bisector
∠CBH ≅ ∠HBK
m∠CBH = m∠HBK = 1/2m∠B
CK is angle C bisector, then by definition of angle bisector
∠BCK ≅ ∠KCH
m∠BCK = m∠KCH = 1/2m∠C
Since m∠B = m∠C, then
m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)
Consider triangles CBH and BCK. In these triangles,
- ∠CBH ≅ ∠BCK (from equality (*));
- ∠HCB ≅ ∠KBC, because m∠B = m∠C;
- BC ≅CB by reflexive property.
So, triangles CBH and BCK are congruent by ASA postulate.
Congruent triangles have congruent corresponding sides, hence
BH ≅ CK.
Answer:
Step-by-step explanation:
Applying BODMAS here;
We first solve what is in the brackets:
9x - 81 -3 = -8x - 16
We then put the like terms together:
9x + 8x = -16 + 81 + 3
We then do the addition:
17x = -16 + 84
We then do the subtraction:
17x = 68
Simplifying this gives:
x = = 4