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miv72 [106K]
3 years ago
8

Which of these shows the graph for the quadratic function y = –2x^2 + 5x – 3?

Mathematics
1 answer:
sladkih [1.3K]3 years ago
4 0
It would be D. The line passes through (1,0) and (1.5,0). If you dont know then you can use the desmos graphing calculator
You might be interested in
What does 5 and 3/8 equal
Wewaii [24]

Answer:

If you want the improper fraction 43/8

If you want it in a decimal 5.375

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
USE DISTANECE= RATE * TIME
torisob [31]
A]
D=R×t
d=5.8r
d2=5.1(r+7)
0.7r=35.7
r=51 mi/hr
thus the average speed on the outbound trip would be:
51+7=58 mi/hr

b]
let speed of fishing boat=x km/h
speed of cruise ship=(x+12.5) km/h
distance traveled by fishing boat=11.5×x=11.5x km
distance traveled by cruise ship=(x+12.5)×11=(11x+137.5) km
Total distance covered by the ships:
11.5x+11x+137.5=322
22.5x=322-137.5
22.5x=184.5
thus
x=184.5/22.5
x=8.2 km/h
The speed of fishing boat is 8.2 km/hr





4 0
4 years ago
Read 2 more answers
Defining Terms
____ [38]

Answers: line DB

H

D

7 0
4 years ago
The table gives estimates of the world population, in millions, from 1750 to 2000. year population year population 1750 790 1900
Tems11 [23]
The poopulation exponential model is given by

P(t)=P_0e^{kt}

Where, P(t) is the population after year t; Po is the initial population, t is the number of years from the starting year; k is the groth constant.

Given that the population in 1750 is 790 and the population in 1800 is 970, we obtain the population exponential equation as follows:

970=790e^{50k} \\  \\ \Rightarrow e^{50k}=1.228 \\  \\ \Rightarrow 50k=\ln{1.228}=0.2053 \\  \\ \Rightarrow k=0.0041

Thus, the exponential equation using the 1750 and the 1800 population values is P(t)=790e^{0.0041t}

The population of 1900 using the 1750 and the 1800 population values is given by

P(t)=790e^{0.041\times150} \\  \\ =790e^{0.6158}=790(1.8511) \\  \\ =1,462

The population of 1950 using the 1750 and the 1800 population values is given by

P(t)=790e^{0.041\times200} \\  \\ =790e^{0.821}=790(2.2729) \\  \\ =1,796

From the table, it can be seen that the actual figure is greater than the exponential model values.
7 0
3 years ago
I need help answering that I’m lost and it’s a 3 step problem
Inessa05 [86]
Hi hi hi i believe 32
3 0
3 years ago
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