A sports club is holding a fundraiser dinner. The function graphed models the profit, y, in dollars, from selling x tickets.

Mathematics

2 answers:

Ymorist [56]3 years ago

7 0

1. true 2. false 3.true

lukranit [14]3 years ago

3 0

Answer: False false true

Step-by-step explanation:

Here to help :D

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Your business partner describes this as a high positive correlation. Is your partner correct? Why or why not? (2 points)

zaharov [31]

Answer:

if the points are in a straight line going upward then they are corect

but if the points are scattered they are wrong its hard to answer this question he graph to look at

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3 years ago

A store pays $22 for a duffel bag. The store marks up the price by

fredd [130]

Marks UP the price by 30%.

There's two ways:
30% of $22, plus $22.
OR
130% of $22.

To save time, 130% of 22.

130/100 x 22
= 13/10 x 22
=13/5 x 11
=143/5
= 28.6

$28.6

Hope this helps!

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3 years ago

E) During free time in school Zain finished 7/8 of the problems from his

TiliK225 [7]

Answer:

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Step-by-step explanation:

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3 years ago

Find (a) arc length and (b) Area of a sector.

barxatty [35]

Answer:

a) 29.45 cm (2 dp)

b) 220.89 cm² (2 dp)

Step-by-step explanation:

<u>Formula</u>

$\textsf{Arc length}=r \theta$

$\textsf{Area of a sector}=\dfrac{1}{2}r^2 \theta$

$\quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle in radians)}$

<u>Calculation</u>

Given:

$\theta=\dfrac{5 \pi}{8}$
r = 15 cm

$\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 15\left(\dfrac{5 \pi}{8}\right)\\& = \dfrac{75}{8} \pi \\& = 29.45\: \sf cm\:(2\:dp)\end{aligned}$

$\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(15^2) \left(\dfrac{5 \pi}{8}\right)\\\\& = \dfrac{225}{2}\left(\dfrac{5 \pi}{8}\right)\\\\ & = \dfrac{1125}{16} \pi \\\\& = 220.89 \: \sf cm^2\:(2\:dp)\end{aligned}$