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Mamont248 [21]
3 years ago
12

For a language test with normally distriuted scores, the mean was 70 and the standard deviation was 10. Approximately what perce

ntage of test takers scored a 60 or above?
Mathematics
1 answer:
Alborosie3 years ago
6 0

Answer: 84.13%

Step-by-step explanation:

Given : The scores in a a language test with normally distributed.

Mean : \mu=70

Standard deviation: \sigma= 10

Let x be the random variable that represents the scores of students.

Formula for z-score: z=\dfrac{x-\mu}{\sigma}

For x= 60 , we have

z=\dfrac{60-70}{10}=-1

The probability f test takers scored a 60 or above :-

P(x\geq60)=P(\geq-1)=1-P(z

Hence, the percentage of test takers scored a 60 or above = 84.13%

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