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zheka24 [161]
3 years ago
15

Draw a figure, A, a line of reflection, L, and a vector FG in the space below. Show that under a sequence of a translation and a

reflection, that the sequence of the reflection followed by the translation is not equal to the translations followed by the reflection. Label the figure as A' after finding the location according to the sequence reflection followed by the translations, and label the figure A'' after finding the location according to the composition translation followed by the reflection. If A' is not equal to A'', then we have shown that the sequence of the reflection followed by a translation is not equal to the sequence of the translation followed by the reflection.
please please answer!!
SAT
1 answer:
raketka [301]3 years ago
4 0

Answer:

bure

Explanation:

hiß haoi óie den la Opie ñsji cßns

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marishachu [46]

Answer:

4

Explanation:

Since it's a flippy number, we can set each digit into ababa

Since it can be divisible by 15, which means it can be divisible by both 5 and 3.

Since it is divisible by 5, the last digit will be either 0 and 5, but it cannot be 0 because 0 cannot be the first digit, so last digit must be 5.

So, ababa --> 5b5b5

It can also be divisible by 3. According to de divisibility rule of 3, if the sum of all digit is divisible by 3 then the number is divisible by 3.

Sum of all digits = 15 + 2b

it's divisible by 3 when b = 0,3,6,9

The answer is 4.

There are 4 such number.

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A waitress sold 20 ribeye steak dinners and 12 grilled salmon​ dinners, totaling ​$559.11 on a particular day. Another day she s
Alexus [3.1K]

Answer:

  • Ribeye steak dinner ≈ $16.01
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Explanation:

  • <em>Number of ribeye steak dinners sold = x</em>
  • <em>Number of grilled salmon dinners sold = y</em>

Create two equations showing the amount sold and earned each day:

\left \{ {{20x+12y=559.11} \atop {29x+6y=583.72}} \right.

Solve the system of equations:

\left \{ {{20x+12y=559.11} \atop {29x+6y=583.72}} \right.\\\\=\left \{ {{20x+12y=559.11} \atop {29(2)x+6(2)y=583.72(2)}} \right.\\\\=\left \{ {{20x+12y=559.11} \atop {58x+12y=1167.44}} \right.\\\\(20-58)x+(12-12)y=559.11-1167.44\\\\-38x=-608.33\\\\x=\frac{-608.33}{-38} =16.01\\\\20x+12y=559.11\\20(16.01)+12y=559.11\\12y=559.11-20(16.01)\\12y=238.91\\y=19.91

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3 years ago
On the first day of a measles outbreak at a school
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Answer:

first isolate all infected children

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Use the passages Silent Spring and "Save the Redwoods" to answer the following question. Considering the authors’ use of appeals
tino4ka555 [31]

Answer: paragraph 4 of “Save the Redwoods”

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