A set of equation can be set up:
a=b+15
3(a+b)=345
where a is the faster and b is the slower bus.
substitute b+15 into the second equation, so 6b+45=345, and 6b=300, therefore b=50.
we can then figure out that a=65
Answer:
Step-by-step explanation:
It is impossible for the equation to be true no matter what value we assign to the variable. Infinite solutions<span> would mean that any value for the variable would make the </span>equation true. I hope my answer has come to your help. God bless and have a nice day ahead!
Answer:
4
Step-by-step explanation:
Terms appear as components of a formula or equation.
Ex. 2n²
So the terms in that equation are:
2n
5
3p
4n
Hope this helps